Bnp paribas Interview Questions, Process, and Tips

12 %

The work done by A in 8 days is = 8/ 12 = 2/3

Means A alone completes 2/3 part of work.

Remaining work which is (1–2/3) = 1/3 is completed by B in 8–2 = 6 days

So the complete work done by B in 6/(1/3) = 18 days.

B alone can complete the work in 18 days.

2x+x+2x+x = 300m
6x = 300
x = 300/6 = 50m
50m x 100m = 5,000 m2

Let the number of one rupee coins in the bag be x.
Number of 50 paise coins in the bag is 93 – x.
Total value of coins
[100x + 50(93 – x)]paise = 5600 paise
=> x = 74

ANS = 74

D

0,8x= y
y – 0,7y = 270

y= 270 / 0,3
y=900

0,8x=900
x=1125

16

4

brother and sister

So we consider the 2nd statement first. We can form an equation out of it.
14x-6=13y+3=9z+3
Using this, we can understand that the multiple of 14 and the multiple of 13 and 9 must have a difference of 9. The easiest way to ensure that is multiplying it by 9
14*9=126
13*9=117
If the 5th farmer gives 3 apples to the 4th farmer, they would have 123 and 120 apples respectively. However, we also know that the 2nd farmer has 117 apples (13*9=117, and this is a multiple of 9) if the 5th farmer gives 3 apples too the 2nd farmer, the 3rd, 4th and 5th farmers would have 120 apples each.
Now that we got 120, we should check if the first part of the question makes sense along with it. The equation would be
7a+1=11b-1=120
We know that 11*11=121 and 7*17=119. When we add 1 to 119 and subtract 1 from 121, we get 120 for each. In this way, all the farmers have 120 apples each.
Therefore, the 3rd farmer had a yield of 11 per tree and the 4th farmer had a yield of 9 per tree.

75 degrees
30h – 11/2 m = 240 – 165 = 75 ..

P1/P2 = C1*T1/ C2*T2
where P1 = Partner 1’s Profit.
C1 = Partner 1’s Capital.
T1 = Time period for which Partner 1 contributed his capital.
P2 = Partner 2’s Profit.
C2 = Partner 2’s Capital.
T2 = Time period for which Partner 2 contributed his capital
6000/3000= 20,000*6/x*12
x=5000

9

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