8men=6days
Xmen=1/2days
M1=8,D1=6
M2=X,D2=1/2
Formula:
M1*D1=M2*D2
8*6=X*(1/2)
X=8*6*2
X=96
Answer=96
30mins
Let the total time taken to fill the tank be x minutes.
Then, work done by B in half hour + work done by (A+B) in half hour =1.
(
40
1
×
2
x
)+(
60
1
+
40
1
)×
2
x
=1
⇒
80
x
+
48
x
=1
⇒
240
3x+5x
=1
⇒8x=240
⇒x=30 min
6.25
30%
D = 180m
S = 42 – 6 = 36 * 5/18 = 10
T = D/S = 180/10
T = 18s
Complete step-by-step answer:
Investment made by A for 1 year, IA=2000
Investment made by B for 2 year,
IB=2×3000IB=6000
Investment made by C for 2 year,
IC=2×4000IC=8000
The ratio of their investment is given by
IA:IB:IC=2000:6000:8000
To simplify the ratio divide it by 1000,
IA:IB:IC=2:6:8
Now again to simplify divide the ratio by 2,
IA:IB:IC=1:3:4
The total parts of this investment =1+3+4=8
A’s share in the investment is 1 out of the 8 parts; B’s share is 3 out of 8 while C’s share is 4.
Therefore, the profit share of A’s investment of Rs. 2000=18×3200=400.
.
28 hrs
8/15 left.
1/15 * 4 + 1/20 * 4 = 7/15
1 – 7/15 = 8/15
x+8y=20, x=-3y
(-3y)+8y=20
5y=20
y=4
The answer for y is 4
A certain sum amounts to Rs. 1725 in 3 years
and amounts to Rs.1875 in 5 years
so interest of 2 years = 1875 -1725
= 150
so interest of 1 year = 75
so interest of 3 years = 75 × 3 =225 rs
so , Principal = Amount – SI
= 1725 – 225
= 1500 rs
now ,
S.I. = P × N × R /100
75 = 1500 × 1 × R /100
R = 75 / 15
R = 5%
– While the train is moving, the jogger will also be running in the same direction.
– for the head(engine) of the train to get to the current position of the jogger 240m away, it will take:
45km/hr => 12.5m/s => 240/12.5 = 19.2 seconds.
– But in the same period of time, the jogger will still be running and will have moved to a new location by: 9km/hr => 2.5m/s => 2.5 * 19.2 = 48m
To get to the new location at the speed of 12.5m/s will take the train:
48/12.5 = 3.84sec
In this additional time, the jogger will move forward by:
3.84 * 2.5 = 9.6m
at a speed of 12.5m/s, it will take the train less than a second to cover the additional 9.6m
If we add the distance the jogger will cover in 1 second to 9.6, it is still less than what the train can cover per second. let us see (9.6 + 2.5 = 12.1)
Therefore, the head of the train will pass the runner at approximately: 19.2 + 3.84 + 1 => 24.04 seconds.
For the train to completely pass the runner, it will need its whole length of 120m to be in front of the runner.
This will take an additional (9.6 + 2) seconds.
Therefore for the length of the train to be ahead of the runner it will take approx. 35.65 (24.04 + 9.6 + 2) seconds
3days
I would design a voice integrated clock that reads out the time aloud whenever people ask for time
3×3=9