Beyondsoft consulting inc Interview Questions, Process, and Tips

Let cost for apple be a Cost for banana be b and Orange be c

So by first value expression becomes 17a + 13b + 9c =130 ———-1 therefore if you further solve a = (130 – 13b – 9c)/17 ———- 2 the second expression becomes: 13c + 7a + 10b = 100 ———- 3 If you put value of a in second expression it becomes: 13c + 7[(130 – 3b – 9c)/17] +10b = 100

Further if you solve you get value of b:

b = 10 – 2c ———-4

put value of b from 4 in 1

17a + 13 [10 – 2c] + 9c = 130

Further if you solve you find value of a

a = c ———-5

Put 5 in 3

13c + 7c + 10b = 100

further solve you get: c = 1 ———-6

from 5 and 6

a = c = 1 ———-7

Substitute value of c in expression 4

b = 10 – 2c b = 10 -2 * 1 b = 8 ———-8

therefore a + b + c = 10

Avg = 2(X*Y)/X+Y
2*(60*40)/60+40
2*(2400)/100
2*24
48.

360

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Prob(choosing two people who are a couple from 6 couples) = 1/6
We have 5 couple left (10 people)
Prob(choosing a person A from 10 people) = 1/10
Prob(choosing 1 person who is not a couple of A) = 1/8

Prob(choosing 4 people that has exactly one couple) = 1/6*1/8*1/10 = 0.0021

4

I am Srilaxmi. I born and bought-up in WARANGAL. My father Agriculture cum politician and my Mom homemaker. I blessed with three brothers and one sister. My elder brother was married and working as a TA in MPDO office at Warangal. My first younger brother was also married and working with Sushee Infra Pvt Ltd as a Asset Manager at Hyderabad. Younger brother and sister are into their studies. Coming to me I completed my MBA from ICFAI university in 2008 and worked as a Audit assistant in accounting firm for two years. I had actively participated in bank audits i.e. is in CBI (Concurrent audit) and SBI(Statutory audit) during my services. Later I pursued CS Executive and attempted for five times then I give up to clear my M.Com. At present I was studying postal studies of CS Executive programme. My hobbies are reading books and listening to music.

450÷100×30=135
450-135=315
Ans: 315

17and+-12=5-48=-43

both a and b is correct

125

Relative speed = 60 + 90 = 150 km/hr.

= 150 x 5/18 = 125/3 m/sec.

Distance covered = 1.10 + 0.9 = 2 km = 2000 m.

Required time = 2000 x 3/125 = 48 sec.

Which means the train will travel 180 m in 6 seconds so
We need to convert this into minutes
6×10 = 60s= 1 minute.
180×10 = 1800 m train will travel 1.8 km in 1 minute.
1.8×60 = 108 kmph