Ques:- 1) In a club there are certain no. of males and females. If 15 females are absent then no. of males will be twice that of females. If 45 males are absent then female strength will be 5 times that of males. Find no. of males actually present.
Recent Answer : Added by Admin On 2020-05-17 12:01:55:
Let the number of males be given the name M.
Let the number of females be given the name F.
If 15 females are absent, then M will be twice that of
present females.
This means that M = 2 * (F – 15)
M = 2 * F – 30.
or 2 * F – M = 30.
Now if in addition to the 15 females being absent, we also
have 45 males being absent,
then this gives the equation,
(F – 15) = 5 * (M – 45)
which simplifies to
F – 15 = 5 * M – 225
5 * M – F = 210
Pulling the equations together, we get
5 * M – F = 210
-M + 2 * F = 30
Multiply the first equation by 2, and keep the second
equation as is.
10 * M – 2 * F = 420
– M + 2 * F = 30
Add the equations.
9 * M = 450
M = 50
Verify answer.
Calculate F
from – M + 2 * F = 30
-50 + 2 * F = 30
2 * F = 30 + 50
F = 40.
If 15 females are absent, then number of males will be twice
that of females.
40 – 15 = 25.
50 = 2 * 25. Confirmed.
If also 45 males were absent, then female strength would be
5 times that of males.
Female strength is 25 due to the 15 females being absent.
50 – 45 = 5.
25 = 5 * 5. Confirmed.
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transistor is a semiconductor device for amplifying ,controlling and generating the electrical signals.
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Ques:- A train 100 meters long passes a platform 100 meters long in seconds. The speed of the train is
A. 36 km/hr
B. 52 km/hr
C. 72 km/hr
D. 92 km/hr
Recent Answer : Added by ThinkAlike On 2022-03-09 16:31:07:
= 100 + 100 = 200 m
Time taken by train = 10 sec.
∵ Speed = Distance/Time
⇒ Speed of train = 200/10 = 20 m/sec.
∴ Speed of train = 20 × 18/5 = 72 kmph.
In question they left 10 seconds
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Recent Answer : Added by Sabari On 2023-05-12 04:10:16:
5/9
Ques:- A certain sum amounts to Rs.1725 in 3 years and Rs.1875 in 5 years. Evaluate the rate % per annum?
Recent Answer : Added by Admin On 2022-09-29 17:01:21:
A certain sum amounts to Rs. 1725 in 3 years
and amounts to Rs.1875 in 5 years
so interest of 2 years = 1875 -1725
= 150
so interest of 1 year = 75
so interest of 3 years = 75 × 3 =225 rs
so , Principal = Amount – SI
= 1725 – 225
= 1500 rs
now ,
S.I. = P × N × R /100
75 = 1500 × 1 × R /100
R = 75 / 15
R = 5%
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Recent Answer : Added by Sourabh Agarwal On 2020-09-09 14:43:25:
20×20+22×22+24×24= 1460
Numbers is less then 30 because 30 square is 900 we have to take three consecutive number if we take numbers greater than 30 the sum of that numbers wil be greater than 1460.
Ques:- In a row of girls, Bina is 5th from the left and Priyanka is6th from the right. When they exchange their positions, then Bina becomes 13th from the left. What will be Priyanka’s position from the right ?
A. 14th
B. 7th
C. 11th
D. 18th
Recent Answer : Added by SHIVANI VISHNU PATIL On 2021-07-28 15:08:27:
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Ques:- 3 cubes of metal whose edges are 9, 12 and 15 cm respectively, are melted and one new cube is made. Find the edge of the new cube?
Recent Answer : Added by Anna On 2021-10-22 09:13:17:
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let b = 12 * 12 * 12;
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sum = a + b + c;
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41, 43, 47, 53, 61, 71, 73, 81
A. 81
B. 73
C. 71
D. 61
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81
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Recent Answer : Added by Admin On 2020-05-17 12:02:22:
ans is a
Ques:- If second no is twice the first no and first no is thrice the third no.Their avg is 20.Find the greatest no?
Recent Answer : Added by Admin On 2020-05-17 12:01:46:
let the third no be x ,
then the first no is 3x ,
second no is 2*3x ie 6x
average is (3x+6x+x )/3 = 20
10x/3 = 20
x= 60/10 = 6
third no is 6 , second is 6x = 36, first no is 3x = 18
largest no is 36 i.e second no
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Let the number of males be given the name M.
Let the number of females be given the name F.
If 15 females are absent, then M will be twice that of
present females.
This means that M = 2 * (F – 15)
M = 2 * F – 30.
or 2 * F – M = 30.
Now if in addition to the 15 females being absent, we also
have 45 males being absent,
then this gives the equation,
(F – 15) = 5 * (M – 45)
which simplifies to
F – 15 = 5 * M – 225
5 * M – F = 210
Pulling the equations together, we get
5 * M – F = 210
-M + 2 * F = 30
Multiply the first equation by 2, and keep the second
equation as is.
10 * M – 2 * F = 420
– M + 2 * F = 30
Add the equations.
9 * M = 450
M = 50
Verify answer.
Calculate F
from – M + 2 * F = 30
-50 + 2 * F = 30
2 * F = 30 + 50
F = 40.
If 15 females are absent, then number of males will be twice
that of females.
40 – 15 = 25.
50 = 2 * 25. Confirmed.
If also 45 males were absent, then female strength would be
5 times that of males.
Female strength is 25 due to the 15 females being absent.
50 – 45 = 5.
25 = 5 * 5. Confirmed.