Aurora Flight Sciences Interview Questions, Process, and Tips

it was a friday.

if am standing on a ballconi so i see the people what they
are doing and how they are handling with the people and
what they are taking to each and everybody.

If n = no. of revolutions for back wheel
9n = 7n + 10*7
n=315

Let A, B and C be the three 6-faced dice.
Then, according to the question,
Since two dices has to be equal, that value can be any of the 6 faces, i.e., 6C1​ cases.
Now for each case, 2 equal dices can be selected from 3 dices in 3C2​ i.e., 3 ways.
And for each of the above, the third dice can have any of the 5 remaining faces
The possible outcomes are P(A)=61​,P(B)=61​,P(C)=65​,P(A)=61​,P(B)=65​,P(C)=61​ and P(A)=65​,P(B)=61​,P(C)=61​
Hence the required probability = 61​×61​×65​×6×3=21690​=125​

2
6*2=12
12*6=72
72*12=864

B. Wheat

72
Because it is not a square number

22