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d=5
g=1
a=4, b=6,c=2,d=5,e=8,f=3,g=1,h=9,i=7

Rs.265.80

let the total work to be done =1
so a+b+c=1 (say)
then a and b are supposed to do 7/11 th of work
so c= 1- (7/11)
c=4/11
therefore c gets (4/11)*550
=200 is the answer

( e ) None of these

original cost is 100^2 / (100^2 – p^2) Rs

1:2

Yes answer is 18 days

A

225

Violet

The batsman on 98 is on strike. He hits the ball and they run 3. UNFORTUNATELY one of the batsmen doesn`t turn correctly for one of the runs and the umpire calls ONE SHORT and awards only two runs. Therefore the first batsman has his century. There is now 1 ball remaining and one run is required to win. The batsman on strike, however is now the one on 97 runs. He now either hits a 4 or a 6. They win the game and both batsmen scored centuries.

Read more: 3 runs required in 3 balls to win with only a wicket left. The batsmen is on 98 and the runner is on 97. How will both the batsmen score centuries … – 3 runs required in 3 balls to win with only a wicket left. The batsmen is on 98 and the runner is on 97. How will both the batsmen score centuries as well win the match ?

A=P+SI——(1)
sum of money after 30 years = Double the money
A=2P———-(2)

Equate 1 and 2
P+SI=2P
SI=2P-P
SI=P————-(3)

WKT, SI= PTR/100

Equate 3 and SI

P=PTR/100
P=P*30*R/100
R=P*100/P*30
R=100/30 or 10/3 or 3(1/3) %