Ques:- “A soldier loses his way in a thick jungle. At random he walks from his camp but mathematically in an interesting fashion. First he walks one mile East then half mile to North. Then 1/4 mile to West, then 1/8 mile to South and so on making a loop.. Finally how far he is from his camp and in which direction. ..”
Recent Answer : Added by Harsh Shah On 2021-07-22 15:55:58:
Soldier have to move 0.75 miles to West and then 0.375 miles to South to reach the camp.
How:-
Firstly soldier moving 1 mile to East from camp and then 1/2 miles= 0.50 miles to North .
Then it is moving 1/4 miles =0.25 miles to west
And then 1/8 miles =0.125 miles to South
Now we just have to count the difference and minus the value of camp to East with the value of North to west = 1mile – 0.25miles(1/4) = 0.75 miles
Same case with north and south = 0.50 miles(1/2) – 0.125 miles(1/8) = 0.375 miles
Hence proves to return camp the soldier have to move 0.75 miles to west and 0.375 miles to south
Ques:- A girl has 55 marbles. She arranges them in n rows. The nth row consists of n marbles, the (n-1)th row consists of (n-1) marbles and so on. What are the number of marbles in nth row?
Recent Answer : Added by DK BOSS On 2021-07-21 15:26:01:
answer 10
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Recent Answer : Added by MAMIDI LIJITA SREE On 2023-01-21 17:36:38:
1000 cu.m
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Answer=8
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Ques:- A is a working partner and B is a sleeping partner in the business. A puts in Rs.15000 and B Rs.25000, A receives 10% of the profit for managing the business the rest being divided in proportion of their capitals. Out of a total profit of Rs.9600, money received by A is?
Recent Answer : Added by DK BOSS On 2021-07-17 06:18:25:
Answer: 4200
Explanation:
15:25 => 3:5
9600*10/100 = 960
9600 – 960 = 8640
8640*3/8 = 3240 + 960
= 4200
Ques:- Find (7x + 4y ) / (x-2y) if x/2y = 3/2 ?
A. 6
B. 8
C. 7
D. data insufficient
Recent Answer : Added by DK BOSS On 2021-07-15 08:19:28:
x/2y=3/2…
therefore
2x=6y
x=3y
therefor
=21y+4y/3y-2y
=25y/y
=25..
there answer=25
so for the above question, we don’t have an option…so answer
is Data Insufficient..
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A. Rs. 11,250
B. Rs. 10,800
C. Rs. 9000
D. Rs. 8625
Recent Answer : Added by narendra On 2022-09-18 09:03:37:
c
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A. 1220
B. 1250
C. 22030
D. 220030
Recent Answer : Added by Ayush On 2022-09-15 16:35:57:
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A. 14 sec.
B. 15 sec.
C. 16 sec.
D. 17 sec.
Recent Answer : Added by Somaskandhan On 2022-09-22 16:39:53:
17 secs
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Ques:- When x is real what is the least value of (x**2-6*x+5)/(x**2+2*x+1)
Recent Answer : Added by Admin On 2020-05-17 12:01:23:
(x**2 – 6* x + 5) = (x-1)*(x-5)
(x**2 + 2 * x + 1) = (x + 1) * (x+1) = (x+1)**2
For what x is (x-1)*(x-5)/( (x+1)**2) a minimum?
One way to answer this question is by using calculus.
Take the derivative, and set to zero.
Since this is a fraction of polynomials, and a fraction is
zero only if it’s numerator is zero, we need calculate only
the numerator of the derivative and set it to zero.
The numerator of the
Derivative of (x-1)*(x-5)/( (x+1)**2) is
( (x-1) + (x-5) ) ( x+1)**2 – (x-1)(x-5)( 2 (x+1) )
= (2 x – 6) (x+1)**2 – (2) (x-1)(x-5) (x+1)
= 0
Divide through by 2 (x+1)
(x-3)(x+1) – (x-1)(x-5) = 0
(x**2 – 2 x – 3 ) – (x**2 – 6 x + 5) = 0
x**2 – x**2 – 2 x + 6 x – 3 – 5 = 0
4 x – 8 = 0
x = 2
Plugging in x = 2 into the original
(x**2-6*x+5)/(x**2+2*x+1)
gives us (2**2 – 6 * 2 + 5)/(2**2 + 2*2 + 1)
= (4 – 12 + 5) / (4 + 4 + 1) = -3/9 = -1/3
Least value is -1/3
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Ques:- In a class of 60, where girls are twice that of boys, Kamal ranked seventeenth from the top. If there are 9 girls ahead of Kamal, how many boys are after him in rank ?
Recent Answer : Added by Selvakumar A On 2021-10-25 09:20:31:
boys= x
girls=2x
boys+girls= 60
x+2x=60
x=60/3
x=20
kamal=17th rank
9 girls are ahead of kamal
17-9=8
20-8=12 boys are after kamal’s rank
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Soldier have to move 0.75 miles to West and then 0.375 miles to South to reach the camp.
How:-
Firstly soldier moving 1 mile to East from camp and then 1/2 miles= 0.50 miles to North .
Then it is moving 1/4 miles =0.25 miles to west
And then 1/8 miles =0.125 miles to South
Now we just have to count the difference and minus the value of camp to East with the value of North to west = 1mile – 0.25miles(1/4) = 0.75 miles
Same case with north and south = 0.50 miles(1/2) – 0.125 miles(1/8) = 0.375 miles
Hence proves to return camp the soldier have to move 0.75 miles to west and 0.375 miles to south