Aas Interview Questions, Process, and Tips

4

I think experience because if experience brings pay. If someone having experience in any work then he/she can work easily. Although pay is important but not more then experience

x = 5/3y
x – 4 = y + 4
x – 8 = y
x = 5/3 * (x-8)
5/3x – 40/3 = x
2/3x = 40/3
2x = 40
x = 20
y = 20 – 8
y = 12
x + 4 = 24
y – 4 = 8
Ratio is 24:8 , so 3:1

Answer is 45
First we need to subtract those reminders from the respective numbers, then we have to find the hcf of two numbers(numbers got from the subtraction) then you will get the answer.
So,
After subtraction you will get
3026-11 = 3015
5053-13 = 5040
HCF of these two numbers
5 | 3015 5040
3 | 603 1008
3 | 201 336
| 67 112
We can’t find a common diviser since 67 is a prime number
So the HCF = 5 * 3 * 3
= 45
5*3*3 = 45

Ans. 175
Relative speed in m/s=40-22=18X5/18=5m/s
Total distance=125+x m
T=1min=60 s
D=sXt
125+x=5X60
x=175

answer
R-R*d/100-5(1-d/100)

In plan A 7500/- and other amounts in plan B

Joe is fencing in a square area of 576 square feet.
Fence posts, which are needed every three feet, cost 32.00 each.
The fencing cost 4.50 per foot. What is the total cost of the fencing materials?

Solution:-
Area of Square is 576 sq ft.
so, the length of side = root(576) = 24 ft

Since the fencing would be done on the perimeter, we would need that
formula is 4*side = 96 ft.

Number of Fence post needed = 96/3 = 32

1 Fence post cost = 32
32 Fence Post cost = 32 * 32 = 1024

Fencing cost = Perimeter * fencing cost = 96 * 4.5 = 432

Total Cost = 432 + 1024 = 1456

105/29 mins

x-28=(1/3)x
x= 42

50 %of 42 = 21

6561 → 6560/2 [-1]
3280
1640
820
410
205 [+1] =206
103 → [-1] = 102
51 [+1] = 52
26
13 [-1] = 12
6
3 [+1] 4
2
1