Ques:- 2 men r playing tossing a coin. If one of them wins he gets 1$ from the loser. At the end of a no. of games, one of them had lost 3$ and the other won 3 times. How many games did they play?
Recent Answer : Added by Admin On 2022-09-29 15:53:16:
Let and A and B are playing and A has 3$ and B won 3 times.
Total money earn by A = no of games A won – no of games A loss
if A loss game means B won.
Therefore
Total money earn by A = no of games A won – no of games B won
3 = no of games A won -3
no of games A won=6
So
A won = 6 games
B won = 3 games
Hence total no of games is 9
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Ques:- A dishonest shopkeeper professes to sell pulses at the cost price, but he uses a false weight of 950gm. for a kg. His gain is____%.
Recent Answer : Added by Rohit Saha On 2021-09-16 17:27:37:
let’s say the Cost Price is 1000x. (CP)
The selling price is also the same as the Cost price. So, here SP=CP (But he sells 950gm instead of 1000gm)
Instead of 1000gm, he is selling 950 grams at the CP. So he sells 050 gms @1000x price. So his net profit is 50gm.
Now 1000gm is 1000x Rs
So, 50gms is 50x rs. [Apllied Unitary Method]
So his profit percentage is:
Profit Percentage Formula: {(Profit/CP)*100%}
So, Here profit is 50x;
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Recent Answer : Added by Admin On 2020-05-17 12:03:38:
( d ) Neeraj is taller than Nilesh
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A. 60
B. 80
C. 55
D. 50
Recent Answer : Added by Admin On 2020-05-17 12:05:48:
40
40
30
60
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Recent Answer : Added by Gowtham On 2022-09-15 16:37:20:
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Let and A and B are playing and A has 3$ and B won 3 times.
Total money earn by A = no of games A won – no of games A loss
if A loss game means B won.
Therefore
Total money earn by A = no of games A won – no of games B won
3 = no of games A won -3
no of games A won=6
So
A won = 6 games
B won = 3 games
Hence total no of games is 9