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Two trains are moving in the same directions at 65 km/hr and 45 km/hr. The faster train crosses a man in slower train in 18 seconds. The length of the faster train is
A. 100 m
B. 120 m
C. 145 m
D. 180 m

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Two trains are moving in the same directions at 65 km/hr and 45 km/hr. The faster train crosses a man in slower train in 18 seconds. The length of the faster train is
A. 100 m
B. 120 m
C. 145 m
D. 180 m
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13 Answers

  1. Assuming 1st train length is = X mtr.
    Relative speed of both train will be = (65-45)*5/18 = 100/18 Km/Hrs.
    1st train taking time to crossing the boy sitting in slower train is = 18 sec.
    Then equation will be :
    Distance = (Relative Speed) * (total taken Time)
    X = (20*5/18) * (18)
    Then Train distance (X) = 100 Mtrs.

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  2. relative speed is=65-45=20kmph, 20*(5/18)=5.5555m/s
    time=18sec
    distance=speed*time=5.5555*18=100m

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  3. 65-45km/h=20km/h
    D=s*t
    therefore 20km/h * 1000 =20000m * 18/3600
    20000 * 1/200=100m

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  4. relative speed is=65-45=20kmph, 20*(5/18)=5.5555m/s
    time=18sec
    distance=speed*time=5.5555*18=100m

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