A. 100 m
B. 120 m
C. 145 m
D. 180 m
Two trains are moving in the same directions at 65 km/hr and 45 km/hr. The faster train crosses a man in slower train in 18 seconds. The length of the faster train is
Two trains are moving in the same directions at 65 km/hr and 45 km/hr. The faster train crosses a man in slower train in 18 seconds. The length of the faster train is
A. 100 m
B. 120 m
C. 145 m
D. 180 m
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100meter
100
Good
Assuming 1st train length is = X mtr.
Relative speed of both train will be = (65-45)*5/18 = 100/18 Km/Hrs.
1st train taking time to crossing the boy sitting in slower train is = 18 sec.
Then equation will be :
Distance = (Relative Speed) * (total taken Time)
X = (20*5/18) * (18)
Then Train distance (X) = 100 Mtrs.
relative speed is=65-45=20kmph, 20*(5/18)=5.5555m/s
time=18sec
distance=speed*time=5.5555*18=100m
180
A 100
Total Distance =?
Time = 18
20 = (X/18) x (18/5) => 100
100m
65-45km/h=20km/h
D=s*t
therefore 20km/h * 1000 =20000m * 18/3600
20000 * 1/200=100m
65 – 45 = 20 kmph
20 * 5/18 =50/9 m/s
50/9* 18 = 100m/s
100m
relative speed is=65-45=20kmph, 20*(5/18)=5.5555m/s
time=18sec
distance=speed*time=5.5555*18=100m