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Two trains are moving in the same directions at 65 km/hr and 45 km/hr. The faster train crosses a man in slower train in 18 seconds. The length of the faster train is
A. 100 m
B. 120 m
C. 145 m
D. 180 m

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Two trains are moving in the same directions at 65 km/hr and 45 km/hr. The faster train crosses a man in slower train in 18 seconds. The length of the faster train is
A. 100 m
B. 120 m
C. 145 m
D. 180 m
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    20 Answers

    1. Relative speed =65-45km/hr
      Relative speed=20km/hr
      Convert to m/s
      S=20*5/18
      S=5.555
      Length of the faster train =5.55555*18seconds
      =100meters

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    2. A man in slower train ;speed =45 km/h
      Faster train speed = 65 km/h
      crossed speed is =difference of speed = 65km/h – 45 km/h = 20 km/h
      Length of train = (20 *18)/3600=0.1 km = 0.1*1000=100 meter

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    3. 100m

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    4. 100 metres

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    5. Two trains are moving in the same directions at 65 km/hr and 45 km/hr. The faster train crosses a man in slower train in 18 seconds. The length of the faster train is<div class="entry-content"><div class="row123"><div class="col-lg-6"> A. 100 m </div><div class="col-lg-6"> B. 120 m </div><div class="col-lg-6"> C. 145 m </div><div class="col-lg-6"> D. 180 m </div></div> </div>

      100m/s

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    6. 20*1000*18/3600
      360000/3600
      100

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    7. 65 faster train
      45 slower train
      faster train crosses slower one by 20 kmph
      and if it crosses the slower one in 18 sec then the length of faster train is
      20*1000*18/3600
      100m
      so the length of the faster train is 100m

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    8. 100meter

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    9. 100

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    10. Good

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    11. Assuming 1st train length is = X mtr.
      Relative speed of both train will be = (65-45)*5/18 = 100/18 Km/Hrs.
      1st train taking time to crossing the boy sitting in slower train is = 18 sec.
      Then equation will be :
      Distance = (Relative Speed) * (total taken Time)
      X = (20*5/18) * (18)
      Then Train distance (X) = 100 Mtrs.

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    12. relative speed is=65-45=20kmph, 20*(5/18)=5.5555m/s
      time=18sec
      distance=speed*time=5.5555*18=100m

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    13. 180

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    14. Total Distance =?

      Time = 18

      20 = (X/18) x (18/5) => 100

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    15. Two trains are moving in the same directions at 65 km/hr and 45 km/hr. The faster train crosses a man in slower train in 18 seconds. The length of the faster train is<div class="entry-content"><div class="row123"><div class="col-lg-6"> A. 100 m </div><div class="col-lg-6"> B. 120 m </div><div class="col-lg-6"> C. 145 m </div><div class="col-lg-6"> D. 180 m </div></div> </div>

      100m

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    16. 65-45km/h=20km/h
      D=s*t
      therefore 20km/h * 1000 =20000m * 18/3600
      20000 * 1/200=100m

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    17. 65 – 45 = 20 kmph
      20 * 5/18 =50/9 m/s
      50/9* 18 = 100m/s

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    18. 100m

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    19. relative speed is=65-45=20kmph, 20*(5/18)=5.5555m/s
      time=18sec
      distance=speed*time=5.5555*18=100m

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