If second no is twice the first no and first no is thrice the third no.Their avg is 20.Find the greatest no?

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let x,y,z be numbers in order

y=2x,x=3z

(x+y+z)/3=20

(x+2x+(x/3))/9=20

solving

x=18

y=36

z=6

so largest is y=36

let the third no be x ,

then the first no is 3x ,

second no is 2*3x ie 6x

average is (3x+6x+x )/3 = 20

10x/3 = 20

x= 60/10 = 6

third no is 6 , second is 6x = 36, first no is 3x = 18

largest no is 36 i.e second no