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If second no is twice the first no and first no is thrice the third no.Their avg is 20.Find the greatest no?

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If second no is twice the first no and first no is thrice the third no.Their avg is 20.Find the greatest no?
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2 Answers

  1. let x,y,z be numbers in order
    y=2x,x=3z
    (x+y+z)/3=20
    (x+2x+(x/3))/9=20
    solving
    x=18
    y=36
    z=6
    so largest is y=36

  2. let the third no be x ,
    then the first no is 3x ,
    second no is 2*3x ie 6x
    average is (3x+6x+x )/3 = 20
    10x/3 = 20
    x= 60/10 = 6
    third no is 6 , second is 6x = 36, first no is 3x = 18
    largest no is 36 i.e second no