A. 50 km/hr
B. 60 km/hr
C. 70 km/hr
D. 72 km/hr
If a 200 m long train crosses a platform of the same length as that of the train in 20 seconds, then the speed of the train is
If a 200 m long train crosses a platform of the same length as that of the train in 20 seconds, then the speed of the train is
A. 50 km/hr
B. 60 km/hr
C. 70 km/hr
D. 72 km/hr
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D
D
D. 72 km/hr
72
72
D
b
72
72km/hr
D
72km/hr
– Total Distance = 200m + 200m = 400m
Time = 20s
S= D/T
S= (400/20)m/s
S= 20m/s
20m/s – km/hr
20*18/5
= 72Km/hr
Train length= 200
Platform length= 200
Time = 20sec
Sum of lengths= time* speed
200+200= 20* speed
400=20*speed
Speed= 400/20
Speed=20 meter /sec
Convert it into hours i.e 20*18/5
Speed = 72km/hr
72 km/hr..
Speed of the train = Total length of the train + length of the platform
______________________________________
time
= 200 + 200
—————- = 20 m/s = 72 km/hr
20
72 km/hr
cos
a train is of length 200m and crosses the platform of same length 200m in 20 sec
so speed of train is 200+200/20=400/20 m/s
x=3600/20=180
multiply and divide by 180
400*180/20*180 m/s
72000/3600 m/s
72km/hr
D
If train length is 200
Platform Length is = train length
=200m + 200m=400m
=Speed= distance /time
=400/20=20m/s
=20*(18/5)=72km per hor
if train length is 200
platform length is = train length
=200+200=400m
speed=distance/time
=400/20=20m/s
=20*(18/5)=72km/h
72
D
72
Length of train 🚅 = 200m
Platform length= 200m
Time = 20 seconds
So, total length = 200+200 = 400m
Speed = Distance/Time
400/ 20 = 20m/s
Convert into km/hr = 20m/s× (18/5) = 72 km/ hr
72km/hr
72