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# A train of length 150 metres takes 40.5 seconds to cross a tunnel of length 300 metres. What is the speed of the train in km/hr? A. 13.33 B. 26.67 C. 39.16 D. 40

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A train of length 150 metres takes 40.5 seconds to cross a tunnel of length 300 metres. What is the speed of the train in km/hr?
A. 13.33
B. 26.67
C. 39.16
D. 40
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1. 13.33

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2. ANSWER WILL BE (B) THAT IS 26.67.
SOLUTION :-
300/40.50=7.407 per second metres
for 60 second 7.407*60=444.444 metres
for 60 minutes i.e. 1 hours = 444.444*60=26666.666 metres
now metres will be converted into km than 26666.66/1000=26.67

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SORRY FOR INCONVENIENCE

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3. (300/40.5)x3.6

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4. 300m= 0.3km
150 m = 0.15km
Total distance = (0.3+ 0.15) = 0.45
In 40.5s the train crosses 0.45km
In 1s the train crosses (0.45/40.5)km
In 3600s the train crosses (0.45*3600)/40.5 km
= 40 km
Therefore, 40km/hr

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5. 300m= 0.3km
150 m = 0.15km
Total distance = (0.3+ 0.15) = 0.45
In 40.5s the train crosses 0.45km
In 1s the train crosses (0.45/40.5)km
In 3600s the train crosses (0.45*3600)/40.5 km
= 40 km
Therefore, 40km/hr

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6. 13.33kmph

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7. 13.33
cos 3600/40.5=88.88888889
so 800/9 its
150*800/9 m/hr
its 13333.33333 m/hr
so 13.33 km/hr

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8. t=l+x/s

[t=40.5*5/18=11.25]

11.25=450/s
s=450/11.25
s=40km/h

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9. 40km/h

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10. option A

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11. S=((150+300)/40.5)Ă—18/5
40

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12. 40 kmph

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13. 40km/hr

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14. Speed =d/t.
=300/40.5=7.40 m/s.
The speed of the train =7.40X(3600/1000)=26.6 km/hr.
Ans is B.

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15. Distance = 150 + 300 = 450
Time = 40.5 SEC
Speed = (450/40.5) x (18/5) = 40 K/hr

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16. 26.67

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17. Total Distance = 150 + 300 => 450

Time = 40.5

Speed of Train = (450/40.5) x (18/5) => 40 K/hr

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18. 26.67

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19. 40

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20. 26.67

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21. 26.67

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22. 40kmph

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23. 40 kmph

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24. 13.3

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25. 40kmph

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