ANSWER WILL BE (B) THAT IS 26.67.
SOLUTION :-
300/40.50=7.407 per second metres
for 60 second 7.407*60=444.444 metres
for 60 minutes i.e. 1 hours = 444.444*60=26666.666 metres
now metres will be converted into km than 26666.66/1000=26.67
300m= 0.3km
150 m = 0.15km
Total distance = (0.3+ 0.15) = 0.45
In 40.5s the train crosses 0.45km
In 1s the train crosses (0.45/40.5)km
In 3600s the train crosses (0.45*3600)/40.5 km
= 40 km
Therefore, 40km/hr
300m= 0.3km
150 m = 0.15km
Total distance = (0.3+ 0.15) = 0.45
In 40.5s the train crosses 0.45km
In 1s the train crosses (0.45/40.5)km
In 3600s the train crosses (0.45*3600)/40.5 km
= 40 km
Therefore, 40km/hr
39.16
13.33
ANSWER WILL BE (B) THAT IS 26.67.
SOLUTION :-
300/40.50=7.407 per second metres
for 60 second 7.407*60=444.444 metres
for 60 minutes i.e. 1 hours = 444.444*60=26666.666 metres
now metres will be converted into km than 26666.66/1000=26.67
THIS IS WRONG ANSWER.PLEASE DONOT RAISE ANY QUESTION
RIGHT ANSWER IS – “40”.
SORRY FOR INCONVENIENCE
(300/40.5)x3.6
300m= 0.3km
150 m = 0.15km
Total distance = (0.3+ 0.15) = 0.45
In 40.5s the train crosses 0.45km
In 1s the train crosses (0.45/40.5)km
In 3600s the train crosses (0.45*3600)/40.5 km
= 40 km
Therefore, 40km/hr
300m= 0.3km
150 m = 0.15km
Total distance = (0.3+ 0.15) = 0.45
In 40.5s the train crosses 0.45km
In 1s the train crosses (0.45/40.5)km
In 3600s the train crosses (0.45*3600)/40.5 km
= 40 km
Therefore, 40km/hr
13.33kmph
13.33
cos 3600/40.5=88.88888889
so 800/9 its
150*800/9 m/hr
its 13333.33333 m/hr
so 13.33 km/hr
t=l+x/s
[t=40.5*5/18=11.25]
11.25=450/s
s=450/11.25
s=40km/h
40km/h
option A
S=((150+300)/40.5)Ă—18/5
40
40 kmph
40km/hr
Speed =d/t.
=300/40.5=7.40 m/s.
The speed of the train =7.40X(3600/1000)=26.6 km/hr.
Ans is B.
Distance = 150 + 300 = 450
Time = 40.5 SEC
Speed = (450/40.5) x (18/5) = 40 K/hr
26.67
Total Distance = 150 + 300 => 450
Time = 40.5
Speed of Train = (450/40.5) x (18/5) => 40 K/hr
26.67
40
26.67
26.67
40kmph
40 kmph
13.3
40kmph
40kmph