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# A train of length 150 metres takes 40.5 seconds to cross a tunnel of length 300 metres. What is the speed of the train in km/hr? A. 13.33 B. 26.67 C. 39.16 D. 40

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A train of length 150 metres takes 40.5 seconds to cross a tunnel of length 300 metres. What is the speed of the train in km/hr?
A. 13.33
B. 26.67
C. 39.16
D. 40
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1. 1km = 1000m
Xkm = 300m
X=0.30km

1hr = 3,600s
X = 40.5s
0.01125hr
Therefore; 0.3km/0.1125hr= 26.6666=26.67km/hr

2. Speed=Distance/Time
Total distance=lenth of the train + length of the tunnel
Total distance=150m+300m=450m
Time=40.5s
Speed( in m/s)= 450/40.5=11.111m/s
Speed(in km/hr)=11.111 x 18/5 = 40 km/hr

3. D.40

4. 40kmph

5. 13.33 KM/HR

6. B

7. 40

8. 40

9. 40km/hr

10. B. 26.67

11. length of train = 150m
length of tunnel= 300m
total = 450m
time = 40.5seconds
speed = distance/time = 450/40.5 = 11.11m/sec
asked in kmph so we need to convert m/sec tp km/hr
11.11*18/5 = 40km/hr

12. Distance Traveled = 300 + 150 = 450
Time taken = 40.5 second
in 1 second the train traveled = 450/40.5 = 11.11111
Seconds in 1 hour = 3600
speed of the train = 3600 x 11.111111 = 40000 meter/hour = 40 km/hour

13. a

14. Why do you all multiply by
5/18? Is this have any reason behind it?

• Why 15/8 ?
Answer:- 1 min = 60 Sec and 1Hrs = 60 Min so when ever we calculate KM/Hrs we need to convert Seconds to Hours so 1hrs=3600 Seconds and 1 Km = 1000 meter so
1000/3600 = 5/18 m/s

1km/hrs = 5/18 m/s
and if we reverse it by cross multiplication
1m/s= 18/5 km/hr

150 + 300 = 450 meters
40.5 seconds

We need to calculate Speed
Seed = Distance / Time (Basic Formula)
so 450/40.5 = 11.11 m/s to convert m/s to km/s we need to multiply by 18/5
so 11.11*18/5 = 40 km/h

15. 40

16. S=((150+300)/40.5)×18/5
40

17. S = D/T
Total distance= length of train + length of tunnel= 450m
S = 450/ 40.5 = 100/9 m/s
Speed in km/hr
100/9 * 18/5 = 40km/hr

18. speed of train = length of tunnel + length of train / time

speed = 300+150/40.5
speed = 300+150/405 * 10
speed = 11.11m/s
now in km/h 11.11*18/5
speed = 39.99 km/h = 40km/h

19. Length of Tunnel = 300m
Length of Train = 150m
Therefore, train will cover 450m to come out of tunnel.
Speed = D/T = 450/40.5
Speed in KM/h = Speed(m/s) x 18/5
Therefore Speed(KM/h) = (450 x 18) / (40.5 x 5) = 40KM/h

20. 40

21. 13.33

22. ANSWER WILL BE (B) THAT IS 26.67.
SOLUTION :-
300/40.50=7.407 per second metres
for 60 second 7.407*60=444.444 metres
for 60 minutes i.e. 1 hours = 444.444*60=26666.666 metres
now metres will be converted into km than 26666.66/1000=26.67

SORRY FOR INCONVENIENCE

23. (300/40.5)x3.6

24. 300m= 0.3km
150 m = 0.15km
Total distance = (0.3+ 0.15) = 0.45
In 40.5s the train crosses 0.45km
In 1s the train crosses (0.45/40.5)km
In 3600s the train crosses (0.45*3600)/40.5 km
= 40 km
Therefore, 40km/hr

25. 300m= 0.3km
150 m = 0.15km
Total distance = (0.3+ 0.15) = 0.45
In 40.5s the train crosses 0.45km
In 1s the train crosses (0.45/40.5)km
In 3600s the train crosses (0.45*3600)/40.5 km
= 40 km
Therefore, 40km/hr

26. 13.33kmph

27. 13.33
cos 3600/40.5=88.88888889
so 800/9 its
150*800/9 m/hr
its 13333.33333 m/hr
so 13.33 km/hr

28. t=l+x/s

[t=40.5*5/18=11.25]

11.25=450/s
s=450/11.25
s=40km/h

29. 40km/h

30. option A

31. S=((150+300)/40.5)×18/5
40

32. 40 kmph

33. 40km/hr

34. Speed =d/t.
=300/40.5=7.40 m/s.
The speed of the train =7.40X(3600/1000)=26.6 km/hr.
Ans is B.

35. Distance = 150 + 300 = 450
Time = 40.5 SEC
Speed = (450/40.5) x (18/5) = 40 K/hr

36. 26.67

37. Total Distance = 150 + 300 => 450

Time = 40.5

Speed of Train = (450/40.5) x (18/5) => 40 K/hr

38. 26.67

39. 40

40. 26.67

41. 26.67

42. 40kmph

43. 40 kmph

44. 13.3

45. 40kmph