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# A train of length 150 m takes 40.5 seconds to cross a tunnel of length of 300 m. The speed of the train (in km/hr) is A. 13.33 B. 26.67 C. 38.32 D. 40

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A train of length 150 m takes 40.5 seconds to cross a tunnel of length of 300 m. The speed of the train (in km/hr) is
A. 13.33
B. 26.67
C. 38.32
D. 40
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1. Ans D. 40 Km/Hour
The length L of the train is 150 Mts, distance to cover D is 300 Mts length of tunnel in time T 40.5 seconds
(L + D)/T = (150+300)/40.5 = 450/40.5 = 11.11 Mts/Sec
Converting the same to Kms/Hour
11.11 * 3600 /1000 = 40 KM/Hour

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2. 40

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3. B

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4. total distance = 150 + 300 = 450m
Time = 40.5s

Distance in km = 450/1000 = 0.45km
Time in hr = 40.5/3600 = 0.01125hr
Speed = distance/time => 0.45/0.01125 => 40km/hr

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5. 40

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6. length of train + tunnel length = total distance
300+150=450
Speed =distance / time
= 450/40.5
It’s was in meter/ second form. We need to convert it into km/hr. So we multiple with 3.6(i.e 3600/1000)
=450/40.5*3.6
=40 km/hr

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7. 40

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8. D

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9. 13.33
total distance pased by train is 150m
because, = tunnel length-train length
=300-150
=150m
d=0.15km t=0.01125

a=d/t
=13.33

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10. 26.667

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11. D. 40

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12. 40

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13. 40 kmph

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14. speed=distance/time=(300+150)/40.5=11.1111m/s=(11.111*(18/5))=40km/hrs

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• How

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