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A train 300 m long crossed a platform 900 m long in 1 minutes 12 seconds. The speed of the train (in km/hr) is
A. 40
B. 50
C. 60
D. 70

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9 Answers

  1. 300+900=1200
    For
    1200 m – 72 sec
    For
    1000m – ?
    Cross multiplication
    1000×72/1200=60 km/h

    • 1
  2. Speed = D/T
    distance is 300+900=1200m
    time is 1 min 12 sec i.e 72sec
    speed = 1200/72 m/sec
    1200/1000=1.2 distance in km
    72/60=1.2, 1.2/60=0.02 time in hours.
    speed = d/t
    => 1.2/0.02 (multiply numerator and denominator by 100)
    =>120/2
    = 60km/hr

    • 0
  3. Total distance to be coverd by train (300+900=1200m)
    Total time taken 72 sec.
    So Speed will be= d/t
    12*100/72=50/3 m/sec
    For Coverting m/sec into km/hr
    We need to multiply it by 18/5
    I.e. 50*18/3*5= 60km/hr

    • 0
  4. Time =1 min 12 s=72 s
    Distance covered in 72 second =300+900=1200 m
    Speed=
    time
    distance

    Speed=(
    72
    1200

    )m/sec=(
    3
    50

    )m/sec=(
    3
    50

    ×
    5
    18

    )=60km/hr

    • -1
  5. Length of train 🚆 = 300 m
    Platform length = 900 m
    Total Length= 300+900 = 1200m
    Speed ⏩ = Distance/Time
    Here, Time is 1 minutes 12 seconds. ( 72 seconds)
    Speed = 1200/72= 16.6667m/s to convert this into km/hr
    For that 16.6667×(18/5) = 60 km/hr

    Good time 😊👍

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