A. 40
B. 50
C. 60
D. 70
A train 300 m long crossed a platform 900 m long in 1 minutes 12 seconds. The speed of the train (in km/hr) is
A train 300 m long crossed a platform 900 m long in 1 minutes 12 seconds. The speed of the train (in km/hr) is
A. 40
B. 50
C. 60
D. 70
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60 km/hr
The answer is
(C.) 60km/hr
300+900=1200
For
1200 m – 72 sec
For
1000m – ?
Cross multiplication
1000×72/1200=60 km/h
Speed = D/T
distance is 300+900=1200m
time is 1 min 12 sec i.e 72sec
speed = 1200/72 m/sec
1200/1000=1.2 distance in km
72/60=1.2, 1.2/60=0.02 time in hours.
speed = d/t
=> 1.2/0.02 (multiply numerator and denominator by 100)
=>120/2
= 60km/hr
Total distance to be coverd by train (300+900=1200m)
Total time taken 72 sec.
So Speed will be= d/t
12*100/72=50/3 m/sec
For Coverting m/sec into km/hr
We need to multiply it by 18/5
I.e. 50*18/3*5= 60km/hr
Time =1 min 12 s=72 s
Distance covered in 72 second =300+900=1200 m
Speed=
time
distance
Speed=(
72
1200
)m/sec=(
3
50
)m/sec=(
3
50
×
5
18
)=60km/hr
Length of train 🚆 = 300 m
Platform length = 900 m
Total Length= 300+900 = 1200m
Speed ⏩ = Distance/Time
Here, Time is 1 minutes 12 seconds. ( 72 seconds)
Speed = 1200/72= 16.6667m/s to convert this into km/hr
For that 16.6667×(18/5) = 60 km/hr
Good time 😊👍
60km/hr
60 km/hr