Admin
  • -1

A train 240 m long passed a pole in 24 seconds. How long will it take to pass a platform 650 m long?
A. 65 sec
B. 79 sec
C. 89 sec
D. 99 sec

  • -1
A train 240 m long passed a pole in 24 seconds. How long will it take to pass a platform 650 m long?
A. 65 sec
B. 79 sec
C. 89 sec
D. 99 sec
Share

Related Questions

Leave an answer

Leave an answer

22 Answers

  1. 240/24=650/x
    650/x=10
    x=650/10
    x=65

  2. speed (S) = D/t
    = 240m/24s
    = 10m/s

    t = D/S
    = 650+240/10
    =890/10
    =89 seconds

    • i have a simple doubt, that why we r not multiplying 18/5….
      which is 3.6 to final answr 10
      like in qsn no 7 telegraph pole) we do..
      136/6 * 3.6 = 22 *3.6 = 79.2 m/s
      so, why not for this qsn..
      240/ 24 * 3.6 = 10 * 3.6 = 36 m/s
      later dividing for 890/36 = 2.4 something
      bt like this we not suppose to do, also i want to know to clear my doubt why we r not multiplying??
      plz can u expalain it out!

  3. for 240 m —– 24 sec
    for 240+650 m—— ?

    Cross multiple 890*24 / 240+89 sec

  4.  240 m long train, the time it takes to cross a pole is 24 seconds,to find the time that the same train will take to cross a 650 m platform. Hence, we got the speed of the train as 10 m/s. From the top calculations, the train will take 89 seconds to cross the platform so the answer is

    (C).89 seconnfd

  5. Actual speed of train 240m/24 sec i.e. 10m/sec..
    Now time taken by train to cross a platform of 650 m will be
    Total distance/speed
    I.e. (650+240)m/10m/sec…
    890m/10m/sec
    89sec

  6. s=D/t
    Train’s speed=240/24=10m/s
    distance=(240+650)=890m
    time=D/s
    time=890/10
    time=89