# A train 240 m long passed a pole in 24 seconds. How long will it take to pass a platform 650 m long? A. 65 sec B. 79 sec C. 89 sec D. 99 sec

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A train 240 m long passed a pole in 24 seconds. How long will it take to pass a platform 650 m long?
A. 65 sec
B. 79 sec
C. 89 sec
D. 99 sec
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1. 65

2. a

3. 65sec

4. 89 second

5. 65

6. 65

7. 240/24=650/x
650/x=10
x=650/10
x=65

8. speed (S) = D/t
= 240m/24s
= 10m/s

t = D/S
= 650+240/10
=890/10
=89 seconds

• i have a simple doubt, that why we r not multiplying 18/5….
which is 3.6 to final answr 10
like in qsn no 7 telegraph pole) we do..
136/6 * 3.6 = 22 *3.6 = 79.2 m/s
so, why not for this qsn..
240/ 24 * 3.6 = 10 * 3.6 = 36 m/s
later dividing for 890/36 = 2.4 something
bt like this we not suppose to do, also i want to know to clear my doubt why we r not multiplying??
plz can u expalain it out!

9. for 240 m —– 24 sec
for 240+650 m—— ?

Cross multiple 890*24 / 240+89 sec

10. 89 sec

11.  240 m long train, the time it takes to cross a pole is 24 seconds,to find the time that the same train will take to cross a 650 m platform. Hence, we got the speed of the train as 10 m/s. From the top calculations, the train will take 89 seconds to cross the platform so the answer is

(C).89 seconnfd

12. A
240:24=650:x
=65

13. 89

14. 240=24
650=X
240X=650X24
X=15600/240
X=65

15. Actual speed of train 240m/24 sec i.e. 10m/sec..
Now time taken by train to cross a platform of 650 m will be
Total distance/speed
I.e. (650+240)m/10m/sec…
890m/10m/sec
89sec

16. s=D/t
Train’s speed=240/24=10m/s
distance=(240+650)=890m
time=D/s
time=890/10
time=89

17. 89sec

18. 65 sec

• if it is a pole then your answer is correct but now it is a platform

19. 89 sec