A. 65 sec
B. 79 sec
C. 89 sec
D. 99 sec
A train 240 m long passed a pole in 24 seconds. How long will it take to pass a platform 650 m long?
A train 240 m long passed a pole in 24 seconds. How long will it take to pass a platform 650 m long?
A. 65 sec
B. 79 sec
C. 89 sec
D. 99 sec
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65
a
65sec
89 second
65
65
240/24=650/x
650/x=10
x=650/10
x=65
speed (S) = D/t
= 240m/24s
= 10m/s
t = D/S
= 650+240/10
=890/10
=89 seconds
i have a simple doubt, that why we r not multiplying 18/5….
which is 3.6 to final answr 10
like in qsn no 7 telegraph pole) we do..
136/6 * 3.6 = 22 *3.6 = 79.2 m/s
so, why not for this qsn..
240/ 24 * 3.6 = 10 * 3.6 = 36 m/s
later dividing for 890/36 = 2.4 something
bt like this we not suppose to do, also i want to know to clear my doubt why we r not multiplying??
plz can u expalain it out!
for 240 m —– 24 sec
for 240+650 m—— ?
Cross multiple 890*24 / 240+89 sec
89 sec
240 m long train, the time it takes to cross a pole is 24 seconds,to find the time that the same train will take to cross a 650 m platform. Hence, we got the speed of the train as 10 m/s. From the top calculations, the train will take 89 seconds to cross the platform so the answer is
(C).89 seconnfd
A
240:24=650:x
=65
65
89
240=24
650=X
240X=650X24
X=15600/240
X=65
Actual speed of train 240m/24 sec i.e. 10m/sec..
Now time taken by train to cross a platform of 650 m will be
Total distance/speed
I.e. (650+240)m/10m/sec…
890m/10m/sec
89sec
s=D/t
Train’s speed=240/24=10m/s
distance=(240+650)=890m
time=D/s
time=890/10
time=89
89sec
65 sec
if it is a pole then your answer is correct but now it is a platform
89 sec