A started at 9.00 am with 6 mph and B started at 9.30 am with 8mph in the same direction. At what time they will meet?

3 Answers on this Question

  1. Let they meet at a distance of x miles
    time taken by A = x/6 and by B – x/8
    x/6 – x/8 = 1/2 (30 min = 1/2 hr)
    4x – 3x = 12
    x = 12 miles
    time taken by A = 12/6 = 2 hr.
    meet at 9:00+ 2 hr = 11:00 am

  2. A’s speed=6 mph ,B’s speed=8 mph
    Let, after x hrs, they will meet.
    so, the distance traveled by A in x hrs should be the same as the distance traveled by B in (x-1/2)hrs [as B started the journey after 30 min of A]
    Thus, 6x=8(x-1/2)[as distance=speed*time]
    after 2 hrs they will meet so time=(9+2)=11.00 a.m

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