A man sees a train passing over a bridge 1 km long. The length of the train is half that of the bridge. If the train clears the bridge in 2 minutes, the speed of the train is

A. 30 km/hr

B. 40 km/hr

C. 45 km/hr

D. 55 km/hr

ridge Length of Bridge = 1 km =1000m
Length of train = half of Bridge = 1000/2 = 500m
total Distance Cover by the train = 1000 + 500 = 1500m
length of train = (1500*3600) / (120 * 1000) = 45 km/h

LENGTH OF BRIDGE = 1KM = 1000 M
LENGTH OF TRAIN = LENGTH OF BRIDGE/2 = 500 M
TOTAL DISTANCE = 1000 + 500 = 1500 M
IF TRAIN CROSS THE 1500 M IN 2 MINUTES
SPEED OF TRAIN = 1500 * 60/2
45000 M
45 KM

S=(length of the train+/length of the bridge)/time
length of the train = length of the bridge/2 = 1km = 1000/2
time = 2 m = 2*60 = 120 s
S=(1500/120)*(18/5)=45 km/h

45km/h

45KM

man saw a train when it has already covered half distance of the bridge so remaining distance of the bridge is 0.5km
The length of the train is half of the bridge = 0.5km
so total distance = 0.5+0.5=1KM
total time is 2min
so speed= 1/(2/60) = 30KM/Hr

30km/hr
because train passed 1km total distance starting bridge to ending take total time is 2 minitues
so that=1/0.033=30.30

Correct option is
B
∴ Speed of the train=45 km/hr

45.45 km/hr approx 45km/hr

Total distance=1+(1/2)=3/2
Time in hours=60/2
Speed of train=3/2×(60/2)=45km/hr

45km