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A 260 meter long train crosses a 120 meter long wall in 19 seconds. What is the speed of the train?
A. 27 km/hr
B. 49 km/hr
C. 72 km/hr
D. 92 km/hr

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A 260 meter long train crosses a 120 meter long wall in 19 seconds. What is the speed of the train?
A. 27 km/hr
B. 49 km/hr
C. 72 km/hr
D. 92 km/hr
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37 Answers

  1. C. 72 KM/Hour
    The length of the train L is 260 Mts and the length of the wall is 120 Mts which we call it as D and the time T taken is 19 Secs
    Speed in Mts/Sec = ( L + D)/T = (260 + 120)/19 = 380/19 = 20M/S
    Converting the same to hours per km
    20 * 3600 = 72000 Mts/Sec = 72000/1000 = 72 Kms

    • 2
  2. total dis=380
    time taken to travel=19 sec
    S=d/t
    s=380/19
    =20
    to covert m/s to km/per we have to multiply with 18/5
    so 20m/s in km/h is
    20m/s=20*18/5=72km/hr

    • 1
  3. 260+120=380 m
    time=19 s
    speed= 380/19 m/s=20 m/s
    in km, speed= (20*3600)/1000 [ 1 hour= 3600 s]

    • -16
  4. Total distance = 260+120=380m
    Time = 19sec
    Speed of train in (m/sec) = total distance/ Time
    = 380/19=20m/sec
    Convert m/sec to km/hr. Short cut(*ly 3.6)
    20*3.6= 72

    • 12
  5. I understand the above answers but when the train has to completely pass the 120 m wall/tunnel, shouldnt the end of train be at the rear end of tunnel? which means distance = 260 + 120 + 260?

    • -3
  6. Total Distance = 260+120=380

    Time = 19

    Speed of Train = (380/19) x (18/5) => 40 K/hr

    • -14
  7. length of train = 260 meters
    length of wall = 120 meters
    Total length = 380 meters
    Remember your answer is in km/hr
    so convert length to km by dividing by 1000
    Hence total length = 380/1000 =0.38

    Time is 19 seconds, convert to hr by dividing by 120
    19/120 = 0.00528 hr

    Speed =distance/time……………0.38/0.00528 =71.97km/hr

    • 3
  8. length of the train is = 260 m
    length of the platform is = 120m
    so total length is = 380m
    and time taken is = 19s
    so v = 380/19
    v = 20m/s

    • -55
  9. train’s length=260m
    wall=120m
    time=19sec
    speed=distance/time
    distance=train’s length+ wall’s length
    so, speed=(260+120)/19=20m/s
    in kms, speed=20*(18/5)=72Km/hr

    • 1
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