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# A 260 meter long train crosses a 120 meter long wall in 19 seconds. What is the speed of the train? A. 27 km/hr B. 49 km/hr C. 72 km/hr D. 92 km/hr

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A 260 meter long train crosses a 120 meter long wall in 19 seconds. What is the speed of the train?
A. 27 km/hr
B. 49 km/hr
C. 72 km/hr
D. 92 km/hr
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1. 72

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2. 20 m/secĂ—18/5=
=72kmph

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3. 72km/hr

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4. C. 72 KM/Hour
The length of the train L is 260 Mts and the length of the wall is 120 Mts which we call it as D and the time T taken is 19 Secs
Speed in Mts/Sec = ( L + D)/T = (260 + 120)/19 = 380/19 = 20M/S
Converting the same to hours per km
20 * 3600 = 72000 Mts/Sec = 72000/1000 = 72 Kms

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5. 72kmph

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6. 72

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7. total dis=380
time taken to travel=19 sec
S=d/t
s=380/19
=20
to covert m/s to km/per we have to multiply with 18/5
so 20m/s in km/h is
20m/s=20*18/5=72km/hr

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8. 72

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9. 260+120=380 m
time=19 s
speed= 380/19 m/s=20 m/s
in km, speed= (20*3600)/1000 [ 1 hour= 3600 s]

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10. 72

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11. 260+120/19
20m/s
also 72kmph

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12. 72

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13. 72

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14. 72km/hr

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15. B. 49

380/19=20 m per sec.

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• 72.. ho my.

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16. 1

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17. 72km/hr

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18. 72km/hr

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19. C

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20. 72km/hr

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21. 72km/hr

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22. 72

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23. C. 72 km/hr

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24. B

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25. Total distance = 260+120=380m
Time = 19sec
Speed of train in (m/sec) = total distance/ Time
= 380/19=20m/sec
Convert m/sec to km/hr. Short cut(*ly 3.6)
20*3.6= 72

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26. I understand the above answers but when the train has to completely pass the 120 m wall/tunnel, shouldnt the end of train be at the rear end of tunnel? which means distance = 260 + 120 + 260?

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27. Total Distance = 260+120=380

Time = 19

Speed of Train = (380/19) x (18/5) => 40 K/hr

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28. 72

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29. length of train = 260 meters
length of wall = 120 meters
Total length = 380 meters
so convert length to km by dividing by 1000
Hence total length = 380/1000 =0.38

Time is 19 seconds, convert to hr by dividing by 120
19/120 = 0.00528 hr

Speed =distance/time……………0.38/0.00528 =71.97km/hr

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• 19/3600 =0.00528
3600 seconds give 1hour

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30. 72km/hr

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31. length of the train is = 260 m
length of the platform is = 120m
so total length is = 380m
and time taken is = 19s
so v = 380/19
v = 20m/s

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32. 72 kmph

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33. train’s length=260m
wall=120m
time=19sec
speed=distance/time
distance=train’s length+ wall’s length
so, speed=(260+120)/19=20m/s
in kms, speed=20*(18/5)=72Km/hr

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34. 72

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