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A 260 meter long train crosses a 120 meter long wall in 19 seconds. What is the speed of the train?
A. 27 km/hr
B. 49 km/hr
C. 72 km/hr
D. 92 km/hr

  • -2
A 260 meter long train crosses a 120 meter long wall in 19 seconds. What is the speed of the train?
A. 27 km/hr
B. 49 km/hr
C. 72 km/hr
D. 92 km/hr
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19 Answers

  1. Total distance = 260+120=380m
    Time = 19sec
    Speed of train in (m/sec) = total distance/ Time
    = 380/19=20m/sec
    Convert m/sec to km/hr. Short cut(*ly 3.6)
    20*3.6= 72

    • 5
  2. I understand the above answers but when the train has to completely pass the 120 m wall/tunnel, shouldnt the end of train be at the rear end of tunnel? which means distance = 260 + 120 + 260?

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  3. Total Distance = 260+120=380

    Time = 19

    Speed of Train = (380/19) x (18/5) => 40 K/hr

    • -1
  4. length of train = 260 meters
    length of wall = 120 meters
    Total length = 380 meters
    Remember your answer is in km/hr
    so convert length to km by dividing by 1000
    Hence total length = 380/1000 =0.38

    Time is 19 seconds, convert to hr by dividing by 120
    19/120 = 0.00528 hr

    Speed =distance/time……………0.38/0.00528 =71.97km/hr

    • 0
  5. length of the train is = 260 m
    length of the platform is = 120m
    so total length is = 380m
    and time taken is = 19s
    so v = 380/19
    v = 20m/s

    • -39
  6. train’s length=260m
    wall=120m
    time=19sec
    speed=distance/time
    distance=train’s length+ wall’s length
    so, speed=(260+120)/19=20m/s
    in kms, speed=20*(18/5)=72Km/hr

    • 0
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