100 glasses are there. A servant has to supply glasses to a
person If he supplies the glasses without any damage he
will get 3 paise otherwise he will loose 3 paise. At the
end of supplying 100 glasses if he gets 270 paise, how many
glasses were supplied safely.
Suppose that x glassses are supplied safely , therefore
(100-x) glases are damage. Then equation is :
3x – 3(100-x) = 270
on solving this equation value of x comes out to be 95.
Wrong again: Answer is 95.
If there are x damaged glasses and y undamaged glasses then
x + y = 100
since each glass delivered undamaged is worth 3 points and
each damaged glass deducts 3 points:
and we know that the net result is 90 glasses worth of
points then:
x – y = 90 —–> x = 90 + y
(90 + y) + y = 100
2*y = 10 —> y = 5
so if number of damaged glasses was 5 then undamaged must
be 100 – 5 = 95
Suppose that x glassses are supplied safely , therefore
(100-x) glases are damage. Then equation is :
3x – 3(100-x) = 270
on solving this equation value of x comes out to be 95.
Wrong again: Answer is 95.
If there are x damaged glasses and y undamaged glasses then
x + y = 100
since each glass delivered undamaged is worth 3 points and
each damaged glass deducts 3 points:
and we know that the net result is 90 glasses worth of
points then:
x – y = 90 —–> x = 90 + y
(90 + y) + y = 100
2*y = 10 —> y = 5
so if number of damaged glasses was 5 then undamaged must
be 100 – 5 = 95