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Ques:- Two trains of equal length when moving in opposite direction takes 5 sec. to cross each other completely and when moving in same direction takes 15 sec. Find the ratio of their speed.
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Recent Answer :
: 21 days
Ques:- YOUR COMPUTER KNOWLEDGE
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Recent Answer :
: 45
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Recent Answer :
: R
T,P,R,Q,S
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Ques:- A train is 360 meter long is running at a speed of 45 km/hour. In what time will it pass a bridge of 140 meter length?
Recent Answer :
: Speed = (45×518)m/sec=252m/sec
Total distance covered = (360+140) m = 500 m.
∴Required time= 500×225sec = 40 sec.
Ques:- The smallest prime number greater than 1000 is
A. 1001
B. 1003
C. 1009
D. 1007
Recent Answer :
: A
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Recent Answer :
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Recent Answer :
: 860
Ques:- Find out the wrong number in a given series.
1, 2, 8, 33, 148, 760, 4626
1, 2, 8, 33, 148, 760, 4626
A. 2
B. 33
C. 148
D. 760
Recent Answer :
: D. 760
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Recent Answer :
: 80
Ques:- Tell me about ur self.
Ques:- 45% of 1500 + 35% of 1700 = ?% of 3175
A. 40
B. 55
C. 45
D. 35
E. None of these
Recent Answer :
: the answer is (a)40
Let’s assume the length of each train is ‘L’ and the speeds of the two trains are ‘V₁’ and ‘V₂’ respectively.
When the trains are moving in the opposite direction, their relative speed is the sum of their individual speeds. The total distance they need to cover is the sum of their lengths. Since they cross each other completely in 5 seconds, we can set up the following equation:
(V₁ + V₂) × 5 = 2L
When the trains are moving in the same direction, their relative speed is the difference between their individual speeds. The total distance they need to cover is the difference between their lengths. Since they cross each other completely in 15 seconds, we can set up the following equation:
(V₁ – V₂) × 15 = 2L
Now, let’s solve these equations to find the ratio of their speeds.
From the first equation, we have:
(V₁ + V₂) × 5 = 2L
V₁ + V₂ = (2L) / 5
From the second equation, we have:
(V₁ – V₂) × 15 = 2L
V₁ – V₂ = (2L) / 15
Let’s add these two equations together:
V₁ + V₂ + V₁ – V₂ = (2L) / 5 + (2L) / 15
2V₁ = (6L + 2L) / 15
2V₁ = (8L) / 15
V₁ = (4L) / 15
So, the speed of the first train is (4L) / 15.
Now, let’s substitute this value back into the first equation to find V₂:
(4L) / 15 + V₂ = (2L) / 5
V₂ = (2L) / 5 – (4L) / 15
V₂ = (6L – 4L) / 15
V₂ = (2L) / 15
Therefore, the speed of the second train is (2L) / 15.
The ratio of their speeds is given by:
(V₁ / V₂) = ((4L) / 15) / ((2L) / 15)
(V₁ / V₂) = 4L / 2L
(V₁ / V₂) = 2
So, the ratio of their speeds is 2:1.