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time (dist covrd by husband) (dist covrd by wife)
0.5hr 20 miles 0 miles
1 hr 40 miles 25 miles
1.5 hr 60 miles 50 miles
2 hrs 80 miles 75 miles
2.5 hrs 100 miles 100 miles
Therefore wife catches up after 2.5 hrs..
Total distance to cover = 132 +110 = 242m
Speed = 72kn/hr = 20m/s
time = 242/20 = 12.1 sec.
the ratio is 4 : 3
so -> let’s suppose a case where multiplying both sides for the same number, the sum of the result will be 28 …
4 * 4 = 16
4 * 3 = 12
16 + 12 = 28
in 8 years they will be respectvely 24 and 20
which is the same as 6/5
5, 15, 30, 135, 405, 1215, 3645
5 is the answer….
Remaining all are the multiples of 3 expect 5
A whole number
5/9
2.88
answer :
Let the distance which I walk to the station be x km Then Time needed to reach the station at 3 km/hr = (3x+602) hrs and
Time needed to reach the station at 4 km/hr = (4x+602) hrs But 3x+301=4x−301⇒3x−4x=−302=151
⇒124x−3x=151⇒12x=151⇒x=1512=54 km
1, 2, 8, 33, 148, 760, 4626
D. 760
= 100 + 100 = 200 m
Time taken by train = 10 sec.
∵ Speed = Distance/Time
⇒ Speed of train = 200/10 = 20 m/sec.
∴ Speed of train = 20 × 18/5 = 72 kmph.
In question they left 10 seconds
Explanation:
72 — 9
? —- 1
=> Down Stream = 8
45 —- 9
? —- 1
=> Up Stream = 5
Speed od current S = ?
S = (8 – 5)/2 = 1.5 kmph.
Take 5 pills from jar 1, 4 pills from jar2,…. and 1 pill
from jar 5 and put altogether in the scale. the ideal
weight should be (1+2+3+4+5)x10= 150gms. for eg if the jar2
is contaminated then the weight will be 146 gms. so
depending on the amount of weight loss we can identify the
contaminated jar.
1>=y>x => y belongs to (-infinity,1]
x belongs to (-infinity,y)
if both x and y are negitive z can be greater than zero and
can be greater than y(1 and 4 are true)
if y equals 1 then x can be equal to z(2 is true)
therefore y=z is not true for any value of x and y