Medcor Interview Questions Answers, HR Interview Questions, Medcor Aptitude Test Questions, Medcor Campus Placements Exam Questions

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This page contains the most recently asked technical questions and answers in the Medcor.

All of the questions listed below were collected by students recently placed at Medcor.

Ques:- if u r traveling from Mumbai to banglore and return back .To find the speed of the car which of the following r needed.
Recent Answer : Added by Admin On 2020-05-17 12:02:19:

i think it is a and b

Ques:- You are standing on top of a tower of ht 200 mt. .At 100 mt. ht . from bottom of tower there is a peg where u can tie a rope. You have a rope of length 150 mt. with you and using this rope you have to get down the tower. you can not jump or there is nobody to help you. how will u get down the tower??
Ques:- There are 9 coins. 8 of them are of 1 gm and 1 is of 2 grams. Find out the heavier coin in minimum number of weighing and how many weighing you need?
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Ques:- The product of two numbers is 120 and the sum of their squares is 289. The sum of the number is?
Recent Answer : Added by Pranali Landkar On 2021-12-17 16:08:24:

23. 15s squre is 225and 8 squre is 64 addition is 289 product also 120 addition 15+8=23

Ques:- X and Y invests Rs.3000 and Rs.4000 respectively in a business. If X doubles his capital after 6 months. In what ratio should X and Y divide that year’s profit?
Ques:- The cost price of a radio is Rs.1500 and it was sold for Rs.1230, find the loss %?
Ques:- The sale price sarees listed for Rs.400 after successive discount is 10% and 5% is?
Ques:- Three 6 faced dice are thrown together. The probability that exactly two dice show the same number on them is -.
Recent Answer : Added by Admin On 2022-09-28 18:05:55:

Let A, B and C be the three 6-faced dice.
Then, according to the question,
Since two dices has to be equal, that value can be any of the 6 faces, i.e., 6C1​ cases.
Now for each case, 2 equal dices can be selected from 3 dices in 3C2​ i.e., 3 ways.
And for each of the above, the third dice can have any of the 5 remaining faces
The possible outcomes are P(A)=61​,P(B)=61​,P(C)=65​,P(A)=61​,P(B)=65​,P(C)=61​ and P(A)=65​,P(B)=61​,P(C)=61​
Hence the required probability = 61​×61​×65​×6×3=21690​=125​

Ques:- Oranges are bought at 11 for a rupee and an equal number more at 9 a rupee. If these are sold at 10 for a rupee, find the loss or gain percent?
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