
Length of the train = 280 meters
Length of the tunnel = 220 meters
Speed of the train = 60 km/h
We are to find the time taken to cross the tunnel.
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✅ Step 1: Total distance to be covered = length of train + length of tunnel
= 280 m + 220 m = 500 meters
✅ Step 2: Convert speed from km/h to m/s
1 km/h = 5⁄18 m/s
So,
60 km/h = 60 × 5⁄18 = 50⁄3 ≈ 16.67 m/s
✅ Step 3: Use the formula
Time = Distance ÷ Speed
= 500 ÷ (50⁄3) = 500 × 3⁄50 = 30 seconds
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✅ Final Answer: The train will take 30 seconds to cross the tunnel.
Length of train = 150 meters
Length of tunnel = 300 meters
Time to cross tunnel = 40.5 seconds
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✅ Step 1: Total distance to be covered = Length of train + Length of tunnel
= 150 m + 300 m = 450 meters
—
✅ Step 2: Use the speed formula:
Speed = Distance / Time
= 450 m / 40.5 s
≈ 11.11 m/s
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✅ Step 3: Convert m/s to km/h:
1 m/s = 3.6 km/h
⇒ 11.11 × 3.6 ≈ 40 km/h
21 mango trees
42 apple trees
56 orange trees
We want to plant them in rows such that:
Each row contains only one type of tree
Each row has the same number of trees
The number of rows is minimized
🧠 This is a Highest Common Factor (HCF) problem.
We need to find the HCF of 21, 42, and 56.
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✅ Step 1: Prime factorizations
21 = 3 × 7
42 = 2 × 3 × 7
56 = 2³ × 7
Common factor = 7
✅ HCF = 7
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✅ Step 2: Find number of rows for each type:
Mango: 21 ÷ 7 = 3 rows
Apple: 42 ÷ 7 = 6 rows
Orange: 56 ÷ 7 = 8 rows
✅ Total rows = 3 + 6 + 8 = 17 rows
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✅ Final Answer: Minimum number of rows = 17