- Gorfine, schiller & gardyn, pa General Aptitude Interview Questions
- Gorfine, schiller & gardyn, pa Trainee Interview Questions
- Gorfine, schiller & gardyn, pa Personal Questions round Interview Questions
- Gorfine, schiller & gardyn, pa HR Interview Questions
- Gorfine, schiller & gardyn, pa Lead Interview Questions
8men=6days
Xmen=1/2days
M1=8,D1=6
M2=X,D2=1/2
Formula:
M1*D1=M2*D2
8*6=X*(1/2)
X=8*6*2
X=96
Answer=96
the answer is 45 km/h
Define x:
Let the total distance be x.
Find the time needed in terms of x for speed at 30 km/h:
Find the time needed in term of x for 40 km./h:
Find the difference in time:
Solve x:
Find the total time needed to for the whole journey:
Given that he was 40 mins late:
Find the minimum speed needed:
Answer: The minimum speed is 45 km/h
16, 32, 64, 81, 100, 144, 190
36
To solve this problem, we can break it down into steps:
Step 1: Determine the individual rates of work for A, B, and C.
If A needs 8 days to finish the task, then their work rate is 1/8 of the task per day.
If B needs 12 days to finish the task, then their work rate is 1/12 of the task per day.
If C needs 16 days to finish the task, then their work rate is 1/16 of the task per day.
Step 2: Calculate the combined work rate of A and B.
If A works for 2 days, their contribution will be 2 * (1/8) = 1/4 of the task completed.
If B works until 25% of the job is left for C, then they will complete 75% of the task.
Step 3: Calculate the time it takes for B to complete 75% of the task.
Since B’s work rate is 1/12 of the task per day, it will take B (75%)/(1/12) = 9 days to complete 75% of the task.
Step 4: Calculate the remaining work for C.
If B completes 75% of the task, then the remaining work for C is 100% – 75% = 25% of the task.
Step 5: Calculate the time it takes for C to complete the remaining work.
Since C’s work rate is 1/16 of the task per day, it will take C (25%)/(1/16) = 4 days to complete the remaining 25% of the task.
Step 6: Calculate the total time required.
A worked for 2 days, B worked for 9 days, and C worked for 4 days, totaling 2 + 9 + 4 = 15 days.
Therefore, it will take a total of 15 days for A to work for 2 days, B to work until 25% of the job is left, and C to complete the remaining work.
445, 221, 109, 46, 25, 11, 4
C.46
4+7
11+(7*2)
25+(7*2*2)
53+(7*2*2*2)
109+(7*2*2*2*2)…..
0
1/24+1/30+1/40=1/10 => 10 days
4/10 = 0.4
1/(24*0.4)+1/(30*0.4) = 0.1875 => 5.33
(10-4) + 5.33 = 11.3 days
d
HCF= 2
LCM = 2*5*7 = 70
17.9