Ques:- 1. A plane travels 695km with wind and 498km aginst the wind in same time.The speed of wind is 21km/hr. Find the speed of plane?
Recent Answer : Added by Admin On 2020-05-17 12:01:01:
127.179(app)
given distance of the train along the wind is 695
and againt the wind is 498
and time = distance/speed
as we know that time is equal in both the cases hence equate
695/s1=498/s2———–(1);
where s1=speed of the plane + speed of the wind
and s2=speed of the plane -speed of the wind
given that speed of the wind is 21k/h
s1=sp+21
s2=sp-21
substitu in eq 1
we get the answer as 27.17(app)
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Recent Answer : Added by DK BOSS On 2021-07-17 06:23:21:
the answer is 3:10
explanation:
let the first number be x
and the second number be y
(7/8)((3/7)x)=(25/100)((45/100)y) given
ie.., 21x/56= 9y/80
on solving we get x:y= 3:10
is the answer
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A. Rs. 11,250
B. Rs. 10,800
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D. Rs. 8625
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Recent Answer : Added by Admin On 2022-09-29 17:39:56:
Answer:
24
Step-by-step explanation:
A + B = 40.
And at Rs 7 a kg for 40 kg, you want a total of Rs.280.
So the second equation is 9A + 4B = 280
From the first equation: B = 40 – A
and sub into the second equation:
9A + 4(40-A) = 280
9A + 160 – 4A = 280
5A = 120
A = 24.
And you should check: B should equal 40-24 = 16. Check with the final equation: 9*24 + 4*16 = 216 + 64 = 280. So it works.
Your answer, of course, is A = 24
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Recent Answer : Added by Soumyadip Dutta On 2022-09-02 17:02:21:
127.179(app)
given distance of the train along the wind is 695
and againt the wind is 498
and time = distance/speed
as we know that time is equal in both the cases hence equate
695/s1=498/s2———–(1);
where s1=speed of the plane + speed of the wind
and s2=speed of the plane -speed of the wind
given that speed of the wind is 21k/h
s1=sp+21
s2=sp-21
substitu in eq 1
we get the answer as 27.17(app)