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Length of the train = 132 meters
Time taken to pass a telegraph pole = 6 seconds
—
✅ Step 1: Use the formula for speed:
Speed = Distance ÷ Time
= 132 m ÷ 6 s = 22 meters/second
—
✅ Step 2: Convert m/s to km/h:
1 m/s = 3.6 km/h
⇒ 22 × 3.6 = 79.2 km/h
—
✅ Final Answer: The speed of the train is 79.2 km/h.
We are given:
January 7, 1992 was a Tuesday
We need to find the day of the week on January 7, 1997 — exactly 5 years later
🧮 Step 1: Count the number of leap years and normal years from 1992 to 1997
From Jan 7, 1992 to Jan 7, 1997 = 5 years
Years: 1992, 1993, 1994, 1995, 1996
Leap years in this range: 1992 and 1996 ⇒ 2 leap years (each adds 2 odd days)
Ordinary years: 1993, 1994, 1995 ⇒ 3 years (each adds 1 odd day)
🧮 Total odd days = (2 × 2) + (3 × 1) = 4 + 3 = 7 odd days
→ 7 odd days = exactly 1 week
So the day of the week remains the same
✅ Final Answer:
January 7, 1997 was also a Tuesday.
We are given:
January 1, 1995 was a Sunday
We are to find the day of the week on January 1, 1996
🟢 Step 1: Determine if 1995 was a leap year
1995 is not divisible by 4 ⇒ Not a leap year
So, it has 365 days
🟢 Step 2: Find the number of odd days in 365 days
365 days = 52 weeks + 1 day ⇒ 1 odd day
So, January 1, 1996 = 1 day after Sunday = Monday
✅ Final Answer:
January 1, 1996 was a Monday.