Commune hotels + resorts Interview Questions, Process, and Tips

Slice the cake

c

8 games They played
A own 3 games = 18 Rs
B loss 3 Rs and own 1 games i,e 9(A own 3 Games)-6(B own
1 game)=3
c own 12 Rs and loss 4 games(A own 3+b own 1) and own 4
games i.e 24(own)-12(loss)
so totally A own 3 games
B own 1 game
c own 4 games
=8

7:8

3606

b

NO but i hope to you hire me

let convert meter to kilometer by multiply 18/5 then answer be 14*(18/5)=50.4 km/s

20

Given y/x = 1/3, x+2y =10
3y=x
Then substitute x=3y in x+2y=10

3y+2y=10
5y=10
y=2

Then substitute y=2 in x=3y
x=3*2
x=6
: x=6, y=2

Reading your question

Answer: 66.67 km approx.

Solution:

Let the first train A move at u km/h.
Let the second train B move at v km/h.
Let the distance between two trains be d km
Let the speed of bee be b km/h
Therefore, the time taken by trains to collide = d/(u+v)
Now putting all the known values into the above equation, we get,

u = 50 km/hr
v = 70 km/hr
d = 100 km
b = 80 km/hr

Therfore, the total distance travelled by bee
= b*d/(u+v)
= 80 * 100/(50+70)
= 66.67 km (approx)

Here is the solution to the given version of the puzzle (9 balls, one is heavier, need to identify oddball), where we label the balls A, B, …, I:

1. Weigh ABC versus DEF.

Scenario a: If these (1) balance, then we know the oddball is one of G, H, I.

2. Weigh G versus H.

Scenario a.i: If these (2) balance, the oddball is I.

Scenario a.ii: If these (2) do not balance, the heavier one is the oddball.

Scenario b: If these (1) do not balance, then the oddball is on the heavier side. For simplicity, assume the ABC side is heavier, so the oddball is one of A, B, C.

2. Weigh A versus B.

Scenario b.i: If these (2) balance, the oddball is C.

Scenario b.ii: If these (2) do not balance, the heavier one is the oddball.

answer is maximum of 2.

How it is possible ? Please write in detail !!! This answer
s not a use !!!

Let the distance between each pole be x m. Then, distance up to 12th pole = 11x m

∴ Speed = 11x22m/s

∴ Time to cover total distance up to 20th pole

= 19x×2411x

= 41.45 s

350m

Use 3pt. Formula
( (x-x1)/(x2-x1) )=( (y-y1)/(y2-y1) )
We get 150

Speed = (45×518)m/sec=252m/sec

Total distance covered = (360+140) m = 500 m.

∴Required time= 500×225sec = 40 sec.