Total inversement =20000
Arun and vinay =40% ,40%
Kamal =20%
8 month gain = 4005
Arun and vinay share of 6 months=1201.5
Kamal share of 6 month = 600.75
Now Arun left, then remaining 2 month’s profits =1001.25
In this case kamal have 33.3% and vinay have remaining percentage of 1001.25
33.3% of 1001.25 is 333.4
Now, total share of kamal is 600.75+333.4=934.16
Reliable Assistance: I promise to provide reliable and accurate assistance in answering questions, providing information, and engaging in meaningful conversations. I strive to deliver helpful and relevant responses to the best of my abilities, drawing from the vast knowledge and information I have been trained on.
Continuous Improvement: I promise to continuously improve my capabilities and expand my knowledge base. As technology evolves and new information becomes available, I aim to stay up-to-date and provide the most accurate and relevant information possible. I strive to enhance my understanding of different topics and improve the quality of my responses over time.
Respectful and Ethical Interaction: I promise to interact with users in a respectful and ethical manner. I am programmed to respect user privacy, confidentiality, and cultural sensitivities, aiming to provide a positive and helpful experience for those who engage with me.
Please note that while I can provide valuable assistance and information, there are certain tasks that may be better suited for human professionals with expertise in specific fields.
One day’s work of A, B and C = (1/24 + 1/30 + 1/40) = 1/10.
C leaves 4 days before completion of the work, which means only A and B work during the last 4 days.
Work done by A and B together in the last 4 days = 4 (1/24 + 1/30) = 3/10.
Remaining Work = 7/10, which was done by A,B and C in the initial number of days.
Number of days required for this initial work = 7 days.
Thus, the total numbers of days required = 4 + 7 = 11 days.
Explanation:
The number of ways of selecting three men, two women and three children is:
= ⁴C₃ * ⁶C₂ * ⁵C₃
= (4 * 3 * 2)/(3 * 2 * 1) * (6 * 5)/(2 * 1) * (5 * 4 * 3)/(3 * 2 * 1)
= 4 * 15 * 10
= 600 ways.
⇒ First part = Rs. 828
A rude person who doesn’t respect me
clicked photos of deer; 14 clicked photos of elephants and deer, 12 clicked photos of tigers and elephants, 15 clicked photos of deer and tigers, and 8 clicked photos of all the three animals. Each tourist took at least one photograph.
1. How many tourists went to the wildlife safari?
2. How many tourists clicked photographs of tigers only?
1. 43 venn diagram
2. 10 using venn diagram
done it roughly chances of having wrong are their..thank u.
(x**2 – 6* x + 5) = (x-1)*(x-5)
(x**2 + 2 * x + 1) = (x + 1) * (x+1) = (x+1)**2
For what x is (x-1)*(x-5)/( (x+1)**2) a minimum?
One way to answer this question is by using calculus.
Take the derivative, and set to zero.
Since this is a fraction of polynomials, and a fraction is
zero only if it’s numerator is zero, we need calculate only
the numerator of the derivative and set it to zero.
The numerator of the
Derivative of (x-1)*(x-5)/( (x+1)**2) is
( (x-1) + (x-5) ) ( x+1)**2 – (x-1)(x-5)( 2 (x+1) )
= (2 x – 6) (x+1)**2 – (2) (x-1)(x-5) (x+1)
= 0
Divide through by 2 (x+1)
(x-3)(x+1) – (x-1)(x-5) = 0
(x**2 – 2 x – 3 ) – (x**2 – 6 x + 5) = 0
x**2 – x**2 – 2 x + 6 x – 3 – 5 = 0
4 x – 8 = 0
x = 2
Plugging in x = 2 into the original
(x**2-6*x+5)/(x**2+2*x+1)
gives us (2**2 – 6 * 2 + 5)/(2**2 + 2*2 + 1)
= (4 – 12 + 5) / (4 + 4 + 1) = -3/9 = -1/3
Least value is -1/3
6.25
60*5/18*9=150
Take 5 pills from jar 1, 4 pills from jar2,…. and 1 pill
from jar 5 and put altogether in the scale. the ideal
weight should be (1+2+3+4+5)x10= 150gms. for eg if the jar2
is contaminated then the weight will be 146 gms. so
depending on the amount of weight loss we can identify the
contaminated jar.
w(drown)
these components can be used to add specialized
functionality, such as animation or pop-up menus, to Web
pages, desktop applications, and software development tools.
24 days