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Ans- 6,6 litres
Let x Litres from can1 (where, water = x/4 litres and milk = 3x/4 litres)
Now
12-x liters from can 2 ( where, water = 6-x/2, milk = 6-x/2)
Now given
water/milk = 3/5
0.25x+6-0.5x / 0.75 +6-0.5x = 3/5
6-0.25x/6+0.25 = 3/5
Solve it you get
x = 6 litres from can1
Then 12-x= 12-6=6 litres from can2
1/x+1/3x=1/36
4/3x=1/36
36*4=3x
X=48
So the slower pipe alone fill the tank in 48 minutes.
125, 106, 88, 76, 65, 58, 53
88
9, 11, 15, 23, 39, ?
71
P+C+M=80
P+C=70
Therefore M=10
Given , P+M=90
If M=10
P=80
Let ‘N’ is the smallest number which divided by 13 and 16 leaves respective remainders of 2 and 5.
Required number = (LCM of 13 and 16) – (common difference of divisors and remainders)
= (208) – (11) = 197.
saying 20%alcohol in 15 litre solution.
It means (20/100)*15=3 litres
Now 5 litre of water is added not alcohol.
So it means only the volume of solution is increases by 5 not alcohol.
It means 15+5=20
Now % of alcohol is
(3/20)*100=15%.
Call from HR for interview in an unexpected time!
the sum of first 4 primes numbers =2+3+5+7 =>17
D also increases
D & T are directly proportional
1
4
5, 10, 13, 26, 29, 58, 61, (…..)
122
14
1×2×…100=100!
Number of zeros in product of n numbers =[5n]+[52n]+[53n]+…
Number of zeros in product of 100 numbers =[5100]+[52100]+[53100]
where [.] is greatest integer function
=[20]+[4]+[0.8]=20+4=24