Montran Interview Questions, Process, and Tips

It’s choice A because you take the last to letters and move them to the front then the previous two letters go after them and so on.

4 mins

choosing my career path

2 Leap years
+2 to tuedsay
Thursday is the correct answer

if initially the price was Re 1.the new price nw bcoms to b
0.7..

so ,if the price z 0.7 ,the increment required is 0.3
so % in crement= 0.3/0.7*100=42.87…

125% of s = 60
=> 1.25s = 60
=> s = 60*4/5
=> s = 48

60 – s = 60 – 48 = 12

Thanq saddha

4:2

True

Ans: 60 kph

Suppose Person meets the train everyday at 3 PM at Station A.

His speed is 12kph.

So normally he reaches 5 km before the meeting point (pt B) at (5/12 hr = 25 min before) 2:35PM.

But if he is late by 30 min, then he will reach that point (pt B) by 3:05 PM.

Train is traveling at its normal speed so it covers the distance of 5 Km in 5 min starting from Station A and reaches the meeting point (pt B) at 3:05 PM.

So speed of the train is 5KM/5min = 60 kph.

habeas corpus

LCM of 4,6,8 and 10 are 120
So, the least number of four digits is 120*9=1080 ( <1000 )

(1/2 + 1/2) = 1
2(1 + 1/2) = 3
2(3 + 1/2) = 7
2(7 + 1/2) = 15
2(15 + 1/2) = 31

the answer is 3:10
explanation:

let the first number be x
and the second number be y
(7/8)((3/7)x)=(25/100)((45/100)y) given
ie.., 21x/56= 9y/80
on solving we get x:y= 3:10
is the answer

Relative speed =65-45km/hr
Relative speed=20km/hr
Convert to m/s
S=20*5/18
S=5.555
Length of the faster train =5.55555*18seconds
=100meters