Ques:- There is a 50m long army platoon marching ahead. The last person in the platoon wants to give a letter to the first person leading the platoon. So while the platoon is marching he runs ahead, reaches the first person and hands over the letter to him and without stopping he runs and comes back to his original position. In the mean time the whole platoon has moved ahead by 50m. The question is how much distance did the last person cover in that time. Assuming that he ran the whole distance with uniform speed.
Recent Answer : Added by Admin On 2020-05-17 12:00:37:
The last person covered 120.71 meters.
It is given that the platoon and the last person moved with
uniform speed. Also, they both moved for the identical
amount of time. Hence, the ratio of the distance they
covered – while person moving forward and backword – are
equal.
Let’s assume that when the last person reached the first
person, the platoon moved X meters forward.
Thus, while moving forward the last person moved (50+X)
meters whereas the platoon moved X meters.
Similarly, while moving back the last person moved [50-(50-
X)] X meters whereas the platoon moved (50-X) meters.
Now, as the ratios are equal,
(50+X)/X = X/(50-X)
(50+X)*(50-X) = X*X
Solving, X=35.355 meters
Thus, total distance covered by the last person
= (50+X) + X
= 2*X + 50
= 2*(35.355) + 50
= 120.71 meters
Note that at first glance, one might think that the total
distance covered by the last person is 100 meters, as he
ran the total lenght of the platoon (50 meters) twice.
TRUE, but that’s the relative distance covered by the last
person i.e. assuming that the platoon is stationary.
Ques:- If you come onboard, give me a general idea of what your first overall tasks will be as far as starting a quality effort.
Ques:- About the related field .
Ques:- Jack & Jill went to the hill….In going to hill (upword Direction)…Jack went to the hill first nd waited for Jill for “x” hours.. Jack’s speed was then twice of Jill.. In the down word direction Jill can go 3km in a hour, while Jack can go 1km in 1 hour.. Jill reach the ground 1st nd waited for Jack for “x” hours.. Total journey they traveled is 6 km.. Find the speed of Jack…
Recent Answer : Added by Admin On 2020-05-17 12:03:21:
previous ans wrong again..!!!!
first find x its 2 hours
total journey 6 hrs 3km up and also down
jill takes one hr to come down and jack takes 3 hrs so x
is 2 hours….
And while going up jack goes at 1.5km/hr and jill goes at
0.75 km hr so to travel 3 km they take 2 hrs and 4 hrs
respectively…!!! x again is 2 hrs…
so jack totally takes 5 hrs to travel 6 km
therfore speed is 6/5 km per hour
thats is 1.2 km per hour is the correct answer
Ques:- Your director is in another part of the region when you receive an email from another dept requiring the return of a draft framework for a 2 yr strategic plan by 5pm the same day. You realize the original email was sent on a day when there was IT problems and you are unable to track the original email. realizing the director has not been aware of the requirement, you decide to…..”.
Ques:- What is the missing number in the series. 1, 4, 27, 256, ?, 46656
Recent Answer : Added by Deepikaa Nandakumar On 2022-05-17 09:08:52:
1^1,2^2,3^3,4:^4,5^5,6^6
1,4,27,256,3125,46656
Ques:- How you wil manage dealer network?
Ques:- Could you have done better in your last job?
Ques:- You are a CA would you like to report to a B.Com having experience more than you
Ques:- Can I pursue one additional professional course (MBA) with CA?
Ques:- What is life ?
Ques:- How would you show co-workers the importance of co-operation?
Ques:- 99 ? 11 + 7 x 16 = (?)2
Recent Answer : Added by Admin On 2020-05-17 12:03:35:
( a ) 11
Ques:- Find out the wrong number in a given series.
124, 133, 142, 152, 160
A. 133
B. 142
C. 152
D. 160
Recent Answer : Added by Nolubabalo On 2022-11-06 15:56:59:
2 minuts the speed ofthe train
Ques:- The total expense of a boarding house are partly fixed and partly variable with the number of boarders. The charge is Rs.70 per head when there are 25 boarders and Rs.60 when there are 50 boarders. Find the charge per head when there are 100 boarders?
Recent Answer : Added by Admin On 2020-05-17 12:05:43:
20kmph
Ques:- If in a certain code, TEACHER is written as VGCEJGT, how would DULLARD be written in the same code ?
Recent Answer : Added by sofiya patil On 2020-10-29 16:15:13:
TEACHER is written as VGCEJGT, how would DULLARD ?
T value is 19
V value is 21 ,
here we get to know that there is difference of 1 letter between them.
Answer: FWNNCTF.
Ques:- If the operation,^ is defined by the equation x ^ y = 2x + y,what is the value of a in 2 ^ a = a ^ 3
Recent Answer : Added by Ananya Jignyasha On 2021-07-14 14:29:35:
2^a = 2 x 2+a
a^3= 2 x a + 3
=> 4+a= 2a + 3
=> a = 1
Ques:- A man ate 100 bananas, each day eating 6more than the previous day. How many bananas did he eat on the first day.
Ques:- How many days are you willing to work?
Ques:- “A soldier loses his way in a thick jungle. At random he walks from his camp but mathematically in an interesting fashion. First he walks one mile East then half mile to North. Then 1/4 mile to West, then 1/8 mile to South and so on making a loop.. Finally how far he is from his camp and in which direction. ..”
Recent Answer : Added by Harsh Shah On 2021-07-22 15:55:58:
Soldier have to move 0.75 miles to West and then 0.375 miles to South to reach the camp.
How:-
Firstly soldier moving 1 mile to East from camp and then 1/2 miles= 0.50 miles to North .
Then it is moving 1/4 miles =0.25 miles to west
And then 1/8 miles =0.125 miles to South
Now we just have to count the difference and minus the value of camp to East with the value of North to west = 1mile – 0.25miles(1/4) = 0.75 miles
Same case with north and south = 0.50 miles(1/2) – 0.125 miles(1/8) = 0.375 miles
Hence proves to return camp the soldier have to move 0.75 miles to west and 0.375 miles to south
Ques:- What do you do to prioritized on a given workday?
Ques:- 2056 x 987 = ?
A. 1896172
B. 1936372
C. 1923472
D. 2029272
Recent Answer : Added by Nirbhay Singh On 2021-12-20 03:54:47:
1896172
Ques:- Why you want to leave this current organisation?
Ques:- Do you know local langaguge
Ques:- In the month of october in a year has exactly four Mondays and four Fridays, find what day of week will be on the 20th of November of that year.
Ques:- Tell me something about youself
Ques:- WHY DO YOU WANT TO WORK FOR THIS ORGANIZATION?
Ques:- Consider a NxN matrix in which the elements are either 0 or 1. Find how many such matrixes are possible that are symmetric in nature(the matrix and its transpose count as 1.
Ques:- How do you feel working under pressure?
Ques:- If A,B,C,D,E are 5 members of a family. 4 of them speak truth: 1. E is my mother in law 2. C is my son in law's brother 3. B is my father's brother 4. A is my brother's wife Who speaks false? and what r the relations among them…
To provide the best experiences, we use technologies like cookies to store and/or access device information. Consenting to these technologies will allow us to process data such as browsing behavior or unique IDs on this site. Not consenting or withdrawing consent, may adversely affect certain features and functions.
Functional
Always active
The technical storage or access is strictly necessary for the legitimate purpose of enabling the use of a specific service explicitly requested by the subscriber or user, or for the sole purpose of carrying out the transmission of a communication over an electronic communications network.
Preferences
The technical storage or access is necessary for the legitimate purpose of storing preferences that are not requested by the subscriber or user.
Statistics
The technical storage or access that is used exclusively for statistical purposes.The technical storage or access that is used exclusively for anonymous statistical purposes. Without a subpoena, voluntary compliance on the part of your Internet Service Provider, or additional records from a third party, information stored or retrieved for this purpose alone cannot usually be used to identify you.
Marketing
The technical storage or access is required to create user profiles to send advertising, or to track the user on a website or across several websites for similar marketing purposes.
The last person covered 120.71 meters.
It is given that the platoon and the last person moved with
uniform speed. Also, they both moved for the identical
amount of time. Hence, the ratio of the distance they
covered – while person moving forward and backword – are
equal.
Let’s assume that when the last person reached the first
person, the platoon moved X meters forward.
Thus, while moving forward the last person moved (50+X)
meters whereas the platoon moved X meters.
Similarly, while moving back the last person moved [50-(50-
X)] X meters whereas the platoon moved (50-X) meters.
Now, as the ratios are equal,
(50+X)/X = X/(50-X)
(50+X)*(50-X) = X*X
Solving, X=35.355 meters
Thus, total distance covered by the last person
= (50+X) + X
= 2*X + 50
= 2*(35.355) + 50
= 120.71 meters
Note that at first glance, one might think that the total
distance covered by the last person is 100 meters, as he
ran the total lenght of the platoon (50 meters) twice.
TRUE, but that’s the relative distance covered by the last
person i.e. assuming that the platoon is stationary.