Grandma
Answer: 40
Explanation:
800*(25/100) = 200 —- 5
? —- 1 => Rs.40
11
Servlets are faster as compared to JSP, as they have a short response time.
JSP is slower than Servlets – JSP is a HTML-based codes.
Servlets are harder to code, as here, the HTML codes are written in Java – JSPs are easier to code, as here Java is coded in HTML.
In an MVC architecture, Servlets act as the controllers. – In MVC architectures, the JSPs act as a view to present the output to the users.
The service() function can be overridden in Servlets. – The service() function cannot be overridden in JSPs.
125, 106, 88, 76, 65, 58, 53
88
Let and A and B are playing and A has 3$ and B won 3 times.
Total money earn by A = no of games A won – no of games A loss
if A loss game means B won.
Therefore
Total money earn by A = no of games A won – no of games B won
3 = no of games A won -3
no of games A won=6
So
A won = 6 games
B won = 3 games
Hence total no of games is 9
Answer:270
Explanation: Formula is SI= P*R*T/100
Where P is principal amount
R is Rate
T is Time
So, SI= 500*6*9/100
i.e SI= 27000/100
SI= 270
– While the train is moving, the jogger will also be running in the same direction.
– for the head(engine) of the train to get to the current position of the jogger 240m away, it will take:
45km/hr => 12.5m/s => 240/12.5 = 19.2 seconds.
– But in the same period of time, the jogger will still be running and will have moved to a new location by: 9km/hr => 2.5m/s => 2.5 * 19.2 = 48m
To get to the new location at the speed of 12.5m/s will take the train:
48/12.5 = 3.84sec
In this additional time, the jogger will move forward by:
3.84 * 2.5 = 9.6m
at a speed of 12.5m/s, it will take the train less than a second to cover the additional 9.6m
If we add the distance the jogger will cover in 1 second to 9.6, it is still less than what the train can cover per second. let us see (9.6 + 2.5 = 12.1)
Therefore, the head of the train will pass the runner at approximately: 19.2 + 3.84 + 1 => 24.04 seconds.
For the train to completely pass the runner, it will need its whole length of 120m to be in front of the runner.
This will take an additional (9.6 + 2) seconds.
Therefore for the length of the train to be ahead of the runner it will take approx. 35.65 (24.04 + 9.6 + 2) seconds
Pearl.. Head cut then earl.. tail cut then pear.. Head and tail cut then ear
name
let a = 9 * 9 * 9;
let b = 12 * 12 * 12;
let c = 15 * 15 * 15;
sum = a + b + c;
edge = Math.cbrt(sum);
console.log(edge);
Daughter-in-law
Phillips
0